To be done using Java with Netbeans. No UML diagrams are needed, just the workin

Question

To be done using Java with Netbeans. No UML diagrams are needed, just the working code.

Two double data fields named x and y that specify the center of the circle with getter methods. A data field radius with a getter method. A no-arg constructor that creates a default circle with (0, 0) for (x, y) and 1 for radius. A constructor that creates a circle with the specified x, y, and radius. A method get Area () that returns the area of the circle. A method getPerimeter () that returns the perimeter of the circle. A method contains (double x, double y) that returns true if the specified point (x, y) is inside this circle (see Figure 10.21a). A method contains(Circle2D circle) that returns true if the specified circle is inside this circle (see Figure 10.21b). A method overlaps(Circle2D circle) that returns true if the specified circle overlaps with this circle (see Figure 10.21c). Figure 10.21 (a) A point is inside the circle, (b) A circle is inside another circle, (c) A circle overlaps another circle. Draw the UML diagram for the class and then implement the class. Write a test program that creates a Circle2D object c1 (new Circle2D(2, 2, 5.5)), displays its area and perimeter, and displays the result of c1.contains(3, 3), c1.contains(new Circle2D(4, 5, 10.5)), and c1.overlaps(new Circle2D(3, 5, 2.3)).

Explanation / Answer

Sample output

Check if 0.2,0.2 lies within the circle
true
Area of the circle with centre 2.0, 2.0 and radius 5.5 is 95.03
Perimeter of the circle with centre 2.0, 2.0 and radius 5.5 is 34.56
Check if 3,3 lies within the circle
true
Check if new circle with centre at 4,5 and radius 10.5 lies with in the previous circle
false
Check if new circle with centre at 3,5 and radius 2.3 overlaps the previous circle
false

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