Specifications for a part for a DVD player state that the part should weigh betw

Question

Specifications for a part for a DVD player state that the part should weigh between 24.4 and 25.4 ounces The process that produces the parts has a mean of 24.9 ounces and a standard deviation of 24 ounce. The distribution of output is normal. Use Table-A a. What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places. Omit the"%" sign in your response.) Percentage of parts b. Within what values will 95.44 percent of sample means of this process fall, if samples of n 7 are taken and the process is in control (random)? (Round your answers to 2 decimal places.) Lower value ounces, Upper value ounces

Explanation / Answer

z = (X - mean)/st dev
z = (25.4 = 24.9)/.24 = .5/.24 = 2.08
2(.0188) = .0376

Percentage of parts = 3.76%

Mean +/- 2(st dev/sqrt(n))
24.9 +/- 2(.24/sqrt(7)) = 24.9 +/- .18
24.72 to 25.08
Lower value = 24.72
Upper value = 25.08

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