Suggest one (1) example of a problematic programming situation or scenario that

Question

Suggest one (1) example of a problematic programming situation or scenario that the use or implementation of a compound if statement could resolve. Justify your response.

Determine whether you believe a compound if statement or a nested if statement is more efficient for your suggested situation / scenario in the first part of this discussion. Provide a rationale for your response

Suggest one (1) example of a problematic programming situation or scenario that a Boolean variable could at least partially resolve. Justify your response

Suggest one (1) example of a problematic programming situation or scenario that a Boolean expression could at least partially solve. Justify your response

Explanation / Answer

An if statement is used to perform a specific action when the given condition is true.

Example:

we want to display a student's Grade basing on marks.

marks    Grade

90 - 100    A

70 - 89      B

40 - 69    C

< 40 D

By using if statement we can solve the problem;

Code snippet:

if( marks >= 90 && marks <= 100)

grade = 'A';

if( marks >= 70 && marks <= 89)

grade = 'B';

if( marks >= 40 && marks <= 69)

grade = 'C';

if( marks <= 39)

grade = 'D';

Basing on the marks range the appropriate grade is assigned.

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2)

However, for the above situation nested if statement is more efficient.

Code snippet:

if( marks >= 90 && marks <= 100)

grade = 'A';

else if( marks >= 70)     // no need to check the max range of marks

grade = 'B';

else if( marks >= 40)    // no need to check the max range of marks

grade = 'C';

else                           // no need to check the max range of marks

grade = 'D';

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3)

Suppose we are checking for a leap year,

A year which is divisible by 4, is a leap year

A year which is divisible by 100, is not a leap year.

A year which is divisible by 400, is a leap year.

Code snippet:

//partial solve

if( year % 4 != 0 || year % 100 == 0)

printf("Non- leap year");

else

printf(" Leap year");

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