public static boolean hasOddStraight(Card[] cards) Five cards (not four) with va

Question

public static boolean hasOddStraight(Card[] cards)

Five cards (not four) with values that are consecutive odd values without "wrapping around" is called an "Odd Straight". For example: 3, 5, 7, 9, J. Keep in mind that the usual order of card values is: A, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A but see the "important note regarding aces", below.

With straights, the Ace behaves a little different from other cards. It can be used either as the "low end" or as the "high end", but not both to try to "warp around".

The part that i need is how to write the part of the code that keeps the ACE at the low or high card.

example (A,3,5,7,J) -> correct way

(3,5,7,J,A)-> Correct way

(3,A,5,7,J) ->Incorrect way

Explanation / Answer

public static boolean hasOddStraight(Card[] cards)
{
   int count =0;

  
   for (int i=0; i<5; i++)
   {
       if (cards[i]== 'A' or cards[i]=='j' or cards[i]== 'Q' or cards[i]=='K')
       {
           if (cards[i]=='A')
           count++;

           if (cards[i]=='Q')
           {
               return false;
               break;
           }
          
       }
       elseif (cards[i]%2==0)
       {
           System.out.println("not and odd straight");
           return false;
           break;
       }
   }
   if (count >1)
       {
           System.out.println("not and odd straight");
           return false;
           break;
       }
  
   for ( int c = 1; c < 4; c++)
   {
       if (cards[i]=='A')
       {
           return false;
           break;  
       }
       else
       return true;  
   }
}

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