NASM Assembly program (x86) that will calculate download times. Program will tak

Question

NASM Assembly program (x86) that will calculate download times. Program will take 4 inputs.

1. Unit of file size (in Bytes) [B,M,K]

2. Unit of network connection (in Bits per second) [B,M,K]

3. The size of the file

4. The speed of the connection

The output of your program will be the time it would take to download the file given the inputs above. Your function must use four parameters on the stack. You must use the stack for your conversion function. You must also save/restore all registers you use in your function, except the eax register, which must be used to return the value of the function(seconds).

You may NOT use global variables (except for strings) and you must use at least 1 local variable and an ebp based stack. You may calculate the time using a floor function so you can round down the amount of time it will take to the nearest second.

Explanation / Answer

section .data ; Messages msg1 db 10,'-Calculator-',10,0 lmsg1 equ $ - msg1 msg2 db 10,'Number 1: ',0 lmsg2 equ $ - msg2 msg3 db 'Number 2: ',0 lmsg3 equ $ - msg3 msg4 db 10,'1. Add',10,0 lmsg4 equ $ - msg4 msg5 db '2. Subtract',10,0 lmsg5 equ $ - msg5 msg6 db '3. Multiply',10,0 lmsg6 equ $ - msg6 msg7 db '4. Divide',10,0 lmsg7 equ $ - msg7 msg8 db 'Operation: ',0 lmsg8 equ $ - msg8 msg9 db 10,'Result: ',0 lmsg9 equ $ - msg9 msg10 db 10,'Invalid Option',10,0 lmsg10 equ $ - msg10 nlinea db 10,10,0 lnlinea equ $ - nlinea section .bss ; Spaces reserved for storing the values ??provided by the user. opc resb 2 num1 resb 2 num2 resb 2 result resb 2 section .text global _start _start: ; Print on screen the message 1 mov eax, 4 mov ebx, 1 mov ecx, msg1 mov edx, lmsg1 int 80h ; Print on screen the message 2 mov eax, 4 mov ebx, 1 mov ecx, msg2 mov edx, lmsg2 int 80h ; We get num1 value. mov eax, 3 mov ebx, 0 mov ecx, num1 mov edx, 2 int 80h ; Print on screen the message 3 mov eax, 4 mov ebx, 1 mov ecx, msg3 mov edx, lmsg3 int 80h ; We get num2 value. mov eax, 3 mov ebx, 0 mov ecx, num2 mov edx, 2 int 80h ; Print on screen the message 4 mov eax, 4 mov ebx, 1 mov ecx, msg4 mov edx, lmsg4 int 80h ; Print on screen the message 5 mov eax, 4 mov ebx, 1 mov ecx, msg5 mov edx, lmsg5 int 80h ; Print on screen the message 6 mov eax, 4 mov ebx, 1 mov ecx, msg6 mov edx, lmsg6 int 80h ; Print on screen the message 7 mov eax, 4 mov ebx, 1 mov ecx, msg7 mov edx, lmsg7 int 80h ; Print on screen the message 8 mov eax, 4 mov ebx, 1 mov ecx, msg8 mov edx, lmsg8 int 80h ; We get the option selected. mov ebx,0 mov ecx,opc mov edx,2 mov eax,3 int 80h mov ah, [opc] ; Move the selected option to the registry ah sub ah, '0' ; Convert from ascii to decimal ; We compare the value entered by the user to know what operation to perform. cmp ah, 1 je add cmp ah, 2 je subtract cmp ah, 3 je multiply cmp ah, 4 je divide ; If the value entered by the user does not meet any of the above ; conditions then we show an error message and we close the program. mov eax, 4 mov ebx, 1 mov ecx, msg10 mov edx, lmsg10 int 80h jmp exit add: ; We keep the numbers in the registers eax and ebx mov eax, [num1] mov ebx, [num2] ; Convert from ascii to decimal sub eax, '0' sub ebx, '0' ; Add add eax, ebx ; Conversion from decimal to ascii add eax, '0' ; We move the result mov [result], eax ; Print on screen the message 9 mov eax, 4 mov ebx, 1 mov ecx, msg9 mov edx, lmsg9 int 80h ; Print on screen the result mov eax, 4 mov ebx, 1 mov ecx, result mov edx, 1 int 80h ; We end the program jmp exit subtract: ; We keep the numbers in the registers eax and ebx mov eax, [num1] mov ebx, [num2] ; Convert from ascii to decimal sub eax, '0' sub ebx, '0' ; Subtract sub eax, ebx ; Conversion from decimal to ascii add eax, '0' ; We move the result mov [result], eax ; Print on screen the message 9 mov eax, 4 mov ebx, 1 mov ecx, msg9 mov edx, lmsg9 int 80h ; Print on screen the result mov eax, 4 mov ebx, 1 mov ecx, result mov edx, 1 int 80h ; We end the program jmp exit multiply: ; We store the numbers in registers ax and bx mov ax, [num1] mov bx, [num2] ; Convert from ascii to decimal sub ax, '0' sub bx, '0' ; Multiply. AL = AX x BX mul bx ; Conversion from decimal to ascii add al, '0' ; We move the result mov [result], al ; Print on screen the message 9 mov eax, 4 mov ebx, 1 mov ecx, msg9 mov edx, lmsg9 int 80h ; Print on screen the result mov eax, 4 mov ebx, 1 mov ecx, result mov edx, 1 int 80h ; We end the program jmp exit divide: ; IN THIS LABEL IS THE ERROR! ; We store the numbers in registers ax and bx mov dx, 0 mov ax, [num1] mov bx, [num2] ; Convert from ascii to decimall sub ax, '0' sub bx, '0' ; Division. AX = DX:AX / BX div bx ; Conversion from decimal to ascii add ax, '0' ; We move the result mov [result], ax ; Print on screen the message 9 mov eax, 4 mov ebx, 1 mov ecx, msg9 mov edx, lmsg9 int 80h ; Print on screen the result ; ALWAYS PRINTS 1 mov eax, 4 mov ebx, 1 mov ecx, result mov edx, 1 int 80h ; We end the program jmp exit exit: ; Print on screen two new lines mov eax, 4 mov ebx, 1 mov ecx, nlinea mov edx, lnlinea int 80h ; End the program mov eax, 1 mov ebx, 0 int 80h

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