#include #include #include using namespace std; string DecimalToBinary(unsigned

Question

#include

#include

#include

using namespace std;

string DecimalToBinary(unsigned int dec){

char binary[33] = {0};

int ix = 32; // subscript of current character

do{

binary[--ix] = '0' + dec % 2;

dec /= 2;

} while (dec);

return (binary+ix); // ix is offset into char array where answer begins

}

int convertBinaryToDecimal(int* n){

int decimalNumber = 0, i = 32, j=0, remainder;

while (i>0){

remainder = n[i];

decimalNumber += remainder*pow(2,j);

++j;

--i;

}

return decimalNumber;

}

int* add(string num1, string num2, int* sum){

int a[32];

int b[32];

int result[32];//, sum[32];

int carry = 0;

for (int k=0; k<32; k++){

a[k] = (int)num1[k];

b[k] = (int)num2[k];

}

for(int i=0; i<4; i++){

if(a[i]+b[i]+carry==3){

result[i]=1;

carry=1;

}

if(a[i]+b[i]+carry==2){

result[i]=0;

carry=1;

}

if(a[i]+b[i]+carry==1){

result[i]=1;

carry=0;

}

if(a[i]+b[i]+carry==0){

result[i]=0;

carry=0;

}

}

result[32]=carry;

for(int j=32; j>=0; j--){

sum[32-j]<

}

}

int main(){

int decimal;

int num1, num2;

string a, b;

int c[32];

cout << "Enter decimal Number: ";

cin >> num1;

cout << " Enter another decimal Number: ";

cin >> num2;

a = DecimalToBinary(num1);

b = DecimalToBinary(num2);

add(a, b, c);

cout<

return 0;

}

There is no error Can you plz check why this program is not compiling .I need it ASAP

Develop a program (in C++) that first asks the user to input a signed number, for example 48 then converts it to binary number by using Two's Complement regulations. Do the same for the second inputted number, e.g., 17. Then compute the summation of these two numbers, output the results in binary format first, then if there is an overflow, display error message; otherwise, convert the result to decimal value and show it on the screen, e.g., 48 (-17) 329. Note that there is no limit to the number of bits your program can handle. For convenience, your program can assume it is for eight bit binary numbers. Also assume all inputs are valid.

Explanation / Answer

Answer:

#include <iostream>
#include <string>
#include <cmath>
using namespace std;
string DecimalToBinary(unsigned int dec){
char binary[33] = {0};
int ix = 32; // subscript of current character
do{
binary[--ix] = '0' + dec % 2;
dec /= 2;
} while (dec);
decimal = (decimal +128)%256 -128;
return (binary+ix); // ix is offset into char array where answer begins
}
int convertBinaryToDecimal(int* n){
int decimalNumber = 0, i = 32, j=0, remainder;
while (i>0){
remainder = n[i];
decimalNumber += remainder*pow(2,j);
++j;
--i;
}
return decimalNumber;
}
int* add(string num1, string num2, int* sum){
int a[32];
int b[32];
int result[32];//, sum[32];
int carry = 0;
for (int k=0; k<32; k++){
a[k] = (int)num1[k];
b[k] = (int)num2[k];
}
for(int i=0; i<4; i++){
if(a[i]+b[i]+carry==3){
result[i]=1;
carry=1;
}
if(a[i]+b[i]+carry==2){
result[i]=0;
carry=1;
}
if(a[i]+b[i]+carry==1){
result[i]=1;
carry=0;
}
if(a[i]+b[i]+carry==0){
result[i]=0;
carry=0;
}
}
result[32]=carry;
for(int j=32; j>=0; j--){
sum[32-j]<
}
}
int main(){
int decimal;
int num1, num2;
string a, b;
int c[32];
cout << "Enter decimal Number: ";
cin >> num1;
cout << " Enter another decimal Number: ";
cin >> num2;
a = DecimalToBinary(num1);
b = DecimalToBinary(num2);
add(a, b, c);
cout<
return 0;
}

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