basic c++ Can someone help with the below program in the simplest form possible

Question

basic c++

Can someone help with the below program in the simplest form possible using only complex conditionals, for or while loops, functions, or arrays. We quickly learned about vectors so I'm not sure if that is what is required to get the below output?

Write a program that reads in names from stdin. Stop reading names when the name is "***DONE***". There will not be more than 100 names, although there may be way fewer. Next, display the second half of the list as shown below:

Reading: Charles

Reading: Debbie

Reading: Larry

Reading: Jerry

Reading: Elaine

Reading: Frank

Reading: George

Reading: Harry

Reading: Adam

Reading: Igor

Reading Betty Ann

Reading ***DONE***

There are 11 names in the list

Listing names 5 through 20

-> Frank

-> George

-> Harry

-> Adam

-> Igor

-> Betty Ann

Explanation / Answer

#include<iostream>
#include<string>
//max 100 names
#define MAX 100
using namespace std;

int main()
{
   //declare array of string to hold names
   string name[MAX];
   //declare variable to cound number of names entered
   int count = 0;
   char ch;
   //take input till user enter CTRL+Z ie EOF
   while (!cin.eof())
   {
       cout << "Reading: ";
       cin >> name[count++];
       fflush(stdin);
   }
   cout << "Reading ***DONE***" << endl;
  
   cout << "There are " << count-1 << " names in the list" << endl;
   //display name from 5 through 20 using for loop
   for (int i = 5; i <= 20; i++)
   {
       if (name[i] != "")
           cout << "->" << name[i] << endl;
   }

}

--------------------------------------------------------------------

output

Reading: Charles
Reading: Debbie
Reading: Larry
Reading: Jerry
Reading: Elaine
Reading: Frank
Reading: George
Reading: Harry
Reading: Adam
Reading: Igor
Reading: Betty Ann
Reading: ^Z
Reading ***DONE***
There are 11 names in the list
->Frank
->George
->Harry
->Adam
->Igor
->Betty

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