A member of a structure or of a class is accessed using the The dot operator Com
ID: 3583404 • Letter: A
Question
A member of a structure or of a class is accessed using the The dot operator Comma operator The indexing operator The ampersand operator A C++ structure, or struct, like the C++ array, is a homogeneous data structure. (i.e., all data is of the same type) True False A structure can have a member whose type is another structure. True False There is no access to private members of a class by any function defined outside the class. True False The dot operator is used between an object and a data member or between a calling object and a call to a member function. True FalseExplanation / Answer
Dear Student,
Here are the answers...
Answer: 1: Option A is correct.
A member of a structure or of a class is accessed using the dot operator(.).
Ex:
struct student
{
int ID;
}Stu1;
here student is the structure and ID is the member, so ID of the student will be accessed in the main function as below.
Stu1.ID;
Answer: 2: False
A C++ structure may contain different data types while a C++ array contains similar data types.
Answer: 3 True
Nesed structures have a member whose type is another structure.
Answer: 4 True
(No outside Access is allowed.)
Yes there is no access to private members of a class by any function defined outside the class.
"If you want to access the private member, you can declare a function/class as friend of that particular class, and then the member will be accessible inside that function or class object without access specifier check."
Answer:5 False
The dot operator is used between an object and a data memebr, not between a calling object and a call to member function.
Ex: emp.name ( here emp is an object and name is the data member )
To access the member functions scope resolution operator [::] is used.
Kindly Check and Verify Thanks...!!!
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