If a link serves 2000 cells/s in an ATM network, has a packet mean size of 300 c
ID: 3583486 • Letter: I
Question
If a link serves 2000 cells/s in an ATM network, has a packet mean size of 300 cells, and a packet loss rate of 10^-3, and each recovery takes 0.5 s. What is the effective throughput of the link? (Show all details, final answer will carry 2 digits after the decimal point) Do the following addresses belong to the same supernet and why? 192.168.21.5/21 192.168.25.20/21 (/21 means that the network address portion of the IP address is made of 21 bits out of the total 32 bits) What is the network address for the host 192.168.21.5/21? C] What is the broadcast address for the host 192.168.21.5/21? Find the oversubscription ratio for 70 subscribers, with the subscribers active r/c = 0.01 of the time, and at most 1% overflow probabilityExplanation / Answer
Ans: 4 )
A)
No ,
192.168.21.5/21 and 192.168.25.20/21 does not belong to same network.
Network 192.168.21.5/21 starts from 192.168.16.0(network address) till 192.168.23.255 (broadcast address).
B)
Network address for the host is 192.168.16.0/21
C)
Broadcast address for 192.168.21.5/21 is 192.168.23.255.
It has three network bit that is 111 (in third octet) (7 in decimal ). Therefore the subnet mask would be (255.255.248 (255-7).0).
Hence the first network starts from 192.168.0.0/21 to 192.168.7.255 , second starts from x.x.8.0/21 to x.x.15.255 , third x.x.16.0/21 to x.x.23.255 and so on.
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