half the matches they play. NOTE: IF POSSIBLE INCLUDING MATLAB PROGRAM WILL BE H

Question

half the matches they play. NOTE: IF POSSIBLE INCLUDING MATLAB PROGRAM WILL BE HELPFUL

it should look something like this (but is incomplete)

function xn = secant3(x0,x1,tol,Nmax)
%SECANT METHOD: Enter f(x), x0, x1, tol, Nmax
f = @(x) ((1+x)/2).*(x./(1-x+x.^2)).^21;
xn = x1 - f(x1)*(x1-x0)/(f(x1)-f(x0));
i = 1;
%yn=f(xn)
%fprintf ('yn=%f',yn);
while (abs(xn - x1) >= tol)
x0 = x1;
x1 = xn;
xn = x1 -f(x1)*(x1-x0)/(f(x1)-f(x0));
i = i + 1;
%c=f(xn);
if (i >= Nmax)
fprintf('Fail after %d iterations ',Nmax);
break
end
%ii=i;
%y=f(xn);
%fprintf('ii=%d,xn=%f,y=%f ',ii,xn,y);
end
end

%i need to find x2,x3,...with number of iterations

Explanation / Answer

tolerance=0.01;

f = @(x) ((1+x)/2).*(x./(1-x+x.^2)).^21;

x0=1;

x1=2;

iterations=1;  

maximumIterations=30;

c=(x0*f(x1)-x1*f(x0))/(f(x1)-f(x0));

while abs(f(c))>tolerance

x0=x1;

x1=c;

c=(x0*f(x1)-x1*f(x0))/(f(x1)-f(x0));

iterations=iterations+1;

if(iterations==maximumIterations)

break;

end

end

if iterations<maximumIterations

disp(['Root of this Equation = ' num2str(c)]);

fprintf('Number of iterations taken: %d ', iterations);

else

disp('Error! Cannot find Root of this equation.');

end

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