Consider a network connection with three links, each with the specified transmis

Question

Consider a network connection with three links, each with the specified transmission rate and link length. Find the end-to-end delay (including the transmission delays and propagation delays on each of the three links, but ignoring queuing delays and processing delays) from when the left host begins transmitting the first bit of a packet to the time when the last bit of that packet is received at the host at the right. The speed of tight propagation delay on each link is 300,000,000 m/sec. te that the transmission rates T1 = 1,437 Mbpa. T2 1,4703lbps, and T3 151 Mbp: and the link distances d1 Assume a packet length 15 Kbits. Give your answer in milliseconds. (Round your answer to two decimal places) 275 Km. d2 304 Km. and d3 290 .

Explanation / Answer

Packet length = 15 Kb = 15 * 103 bits

For the first transmission link:

T1 = 1437 Mbps = 1437 * 106 bps

d1=275 Km = 275 * 103 m

RTT (Round Trip Time) for link 1 = TT(Transmission time) + 2*PT(Propagation Time)

TT for link 1= packet length/ Transmission rate = (15 * 103)/ (1437 * 106) = 0.0104 milliseconds

PT for link 1 = distance/ speed of light = (275 * 103)/(3 * 108) = 0.9167 milliseconds

RTT of link 1 = 0.0104 + 2*0.9167 = 1.8438 milliseconds

Similarly,

For the second transmission link:

T2 = 1470 Mbps = 1470 * 106 bps

d2=304 Km = 304 * 103 m

RTT (Round Trip Time) for link 2 = TT(Transmission time) + 2*PT(Propagation Time)

TT for link 2= packet length/ Transmission rate = (15 * 103)/ (1470 * 106) = 0.0102 milliseconds

PT for link 2 = distance/ speed of light = (304 * 103)/(3 * 108) = 1.1033 milliseconds

RTT of link 2 = 0.0102 + 2*1.1033 = 2.2168 milliseconds

For the third transmission link:

T3 = 151 Mbps = 151 * 106 bps

d3=290 Km = 290 * 103 m

RTT (Round Trip Time) for link 3 = TT(Transmission time) + 2*PT(Propagation Time)

TT for link 3= packet length/ Transmission rate = (15 * 103)/ (151 * 106) = 0.0993 milliseconds

PT for link 3 = distance/ speed of light = (290 * 103)/(3 * 108) = 0.9667 milliseconds

RTT for link 3 = 0.0993+ 2*0.9667 = 2.0327 milliseconds

So, the end to end delay will be the sum of RTT of 3 different links i.e.,

End to end delay = RTT for link 1+ RTT for link 2 + RTT for link 3 = 1.8438 + 2.2168 + 2.0327 = 6.093 milliseconds

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