Implement and test the class named Ternary according to the following class defi

Question

Implement and test the class named Ternary according to the following class definition:
class Ternary {
public:
Ternary();
Ternary(int);
Ternary& operator+=( const Ternary&);
Ternary& operator-=( const Ternary&);
Ternary& operator*=(const Ternary&);
Ternary& operator-();
bool operator==(const Ternary&) const;
bool operator!=(const Ternary&) const;
bool operator<(const Ternary&) const;
bool operator>(const Ternary&) const;
bool operator<=(const Ternary&) const;
bool operator>=(const Ternary&) const;
istream& extract(istream&);
ostream& insert(ostream&) const;
private:
bool isTernary(int) const;
int toDecimal(int) const;
int toTernary(int) const;
int decimal_equivalent;
};
ostream& operator<<(ostream&, const Ternary&);
istream& operator>>(istream&, Ternary&);
const Ternary& operator+(const Ternary&, const Ternary&);
const Ternary& operator-(const Ternary&, const Ternary&);
const Ternary& operator*(const Ternary&, const Ternary&);

In this assignment you will define, implement, and test a C++ class called Ternary to represent and use whole numbers (positive or negative) in base-three number system. In the decimal system or base-ten number system we have 10 symbols or numerals 0,1,2,... ,9 representing values zero, one, two, ..., nine, respectively. In the ternary number system there are only three symbols 0, 1, 2 representing values zero, one, two, respectively. For a multi-digit whole number e.g., 122, its value in decimal systern is computed as (122) 11022 1012 10 one hundred twenty two. In the ternary number system its value Is (122),-1*32 +2 * 31 + 2 * 30-1710-

Explanation / Answer

#include <bits/stdc++.h>

using namespace std;

class Ternary{

int num; // Num is your only private data member

public:

Ternary(){

num = 0;

}

Ternary(int n){ // Convert Base 3 number to Decimal number

int temp = 0, base = 1;

while(n){

int rem = n % 10;

if(rem > 2){ // If anytime rem > 2 number is Invalid

cout << "Invalid Ternary Number : " << rem <<endl;

return;

}

temp += (rem * base);

base *= 3;

n /= 10;

}

num = temp;

}

Ternary plus(const Ternary& r) const;

Ternary minus(const Ternary& r) const;

Ternary times(const Ternary& r) const;

void insert(ostream&);

void extract(istream&);

};

Ternary Ternary::plus(const Ternary& r) const{ // Add number and store it to another number

int a = r.num;

int b = num;

int res = 0 , sum = a+b;

while(sum){ // First convert sum to base 3

res = (res * 10) + sum%3;

sum /= 3;

}

return Ternary(res);

}

Ternary Ternary::minus(const Ternary& r) const{

int a = r.num;

int b = num;

int res = 0 , sub = b - a;

while(sub){ // Convert Subtraction to Base 3

res = (res * 10) + sub%3;

sub /= 3;

}

return Ternary(res);

}

Ternary Ternary::times(const Ternary& r) const{

int a = r.num;

int b = num;

int res = 0 , sub = b * a;

while(sub){ // Convert Times result to Base 3

res = (res * 10) + sub%3;

sub /= 3;

}

return Ternary(res);

}

void Ternary::insert(ostream& out){

out << num << endl;

return;

}

void Ternary::extract(istream& in){

in >> num;

return;

}

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