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Use stack please (Java) In Java Given an array A of n integers, a leader element

ID: 3588246 • Letter: U

Question

Use stack please (Java) In Java Given an array A of n integers, a leader element of the array A is the element that appears more than half of the time in A. Implement in Java an O(n) worst-case algorithm that uses a stack static int leader(int[] A) to find a leader element and return the index (any) of the leader in A. The program must returns -1 if no leader element exists. Examples: int[] a = {23, 23, 67, 23, 67, 23, 45}; ====> leader(a) = 5 int[] a = {23, 24, 67, 23, 67, 23, 45}; ====> leader(a) = -1

Explanation / Answer

// Simple C program to print next greater elements

// in a given array

#include<stdio.h>

/* prints element and NGE pair for all elements of

arr[] of size n */

void printNGE(int arr[], int n)

{

    int next, i, j;

    for (i=0; i<n; i++)

    {

        next = -1;

        for (j = i+1; j<n; j++)

        {

            if (arr[i] < arr[j])

            {

                next = arr[j];

                break;

            }

        }

        printf("%d -- %dn", arr[i], next);

    }

}

int main()

{

    int arr[]= {11, 13, 21, 3};

    int n = sizeof(arr)/sizeof(arr[0]);

    printNGE(arr, n);

    getchar();

    return 0;

}

// Simple C program to print next greater elements

// in a given array

#include<stdio.h>

/* prints element and NGE pair for all elements of

arr[] of size n */

void printNGE(int arr[], int n)

{

    int next, i, j;

    for (i=0; i<n; i++)

    {

        next = -1;

        for (j = i+1; j<n; j++)

        {

            if (arr[i] < arr[j])

            {

                next = arr[j];

                break;

            }

        }

        printf("%d -- %dn", arr[i], next);

    }

}

int main()

{

    int arr[]= {11, 13, 21, 3};

    int n = sizeof(arr)/sizeof(arr[0]);

    printNGE(arr, n);

    getchar();

    return 0;

}