Use while loop or do-while loop to solve the following problems using C Programm

Question

Use while loop or do-while loop to solve the following problems using C Programming.

Q.1 Write a program which will ask the user to enter a number, say M which is larger than 4 and smaller than 20. Then, the computer must list all the numbers from 1 to M in an increasing order followed by all the numbers from M to 1 in a decreasing order. That is if the user enters 5 then the list on the screen must look like: 1 2 3 4 5 4 3 2 1. Can you print the list using only ONE loop (bonus 10 points for the last part)?

Q.2 Write a program that will display on the console a list of N numbers where each number in the list starting from the third one is sum of the previous two. First two numbers in this list are 1 and 1. The value of N should be taken from the user at the beginning of the program. That is, for N=7, your computer should display the following list: 1 1 2 3 5 8 13.

Q.3 Write a program that will print every 4th letter in the English alphabet, starting from ‘A’ and when it reaches the end it keeps printing in a circular manner until every letter is listed at least once, i.e, the list will be like:

A D   G J……V Y B E H……….W Z C F…..

Explanation / Answer

Solution 1:

#include<stdio.h>

int main(){
  
   int M,i=1,flag = 0;
   printf("Enter any between 5 to 19 : ");
   scanf("%d",&M);
  
   while(i!=0){
       printf("%d ",i);
      
       /*
          till i reaches M print i by incrementing.
          when i reaches M print i by decrementing.
          we use flag variable because when decrement started it should be decremented
          if we don't use flag variable this loop will go to infinite
      
       */
       if(i < M && flag == 0){
           i++;
       }
       else{
           flag = 1;
           i--;
       }
   }

    return 0;
}

Sample Output for solution 1:

Enter any between 5 to 19 : 5
1 2 3 4 5 4 3 2 1

Solution 2:

#include<stdio.h>

int main(){
  
   int N,i = 1,j = 0,count = 1;
   printf("Enter any positive number : ");
   scanf("%d",&N);
   while(count <= N){
       /*
           here i is the first element and j is second element
           for every iteration we swap variables i and j.
           And i is incremented by j;
           Count variable is to check how many number are printed till now
       */
       printf("%d ",i);
       int temp = i;
       i = i + j;
       j = temp;
       count++;
   }

    return 0;
}

Sample output for solution 2:

Enter any positive number : 7
1 1 2 3 5 8 13

Solution 3:

#include<stdio.h>

int main(){
  
   int charAscii = 1;
  
   while(charAscii != 24){
      
       /*
           A ascii value is 65. So we are adding 64 to 'charAscii' and printing the character.
           after that we need every fourth element so add 3 to 'charAscii'
           when ever 'charAscii' is greater than 26, then calculate remainder and store it to 'charAscii'.
           this process will continued till 'charAscii' reaches '24'
           If we write that sequence : 1 4 7 10 13 16 19 22 25 2 5 8 11 14 17 20 23 26 3 6 9 12 15 18 21 24
           This is toatl sequence that every character is present atleast one time.
       */
      
       printf("%c ",charAscii + 64);
       charAscii = (charAscii + 3);
       if(charAscii > 26){
           charAscii %= 26;
       }
   }
  
   return 0;
}

Sample output for solution 3:

A D G J M P S V Y B E H K N Q T W Z C F I L O R U

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.