Write in python, syllable_count This function takes a word and returns the numbe

Question

Write in python,

syllable_count

This function takes a word and returns the number of syllables in the word. For this exercise, assume that syllables are determined as follows: Each sequence of vowels a e i o u y, except for the last e in a word, is a vowel. However, if that algorithm yields a count of 0, change it to 1. For example,

the 1

def syllable_count(word):
"""
Returns the number of syllables in the word.
For this exercise, assume that syllables are determined as follows:
Each sequence of vowels a e i o u y, except for the last e in a word, is a vowel.
However, if that algorithm yields a count of 0, change it to 1.

:param word: the word whose syllables are being counted.

>>> syllable_count('Harry')
2
>>> syllable_count('HAIRY')
2
>>> syllable_count('hare')
1
>>> syllable_count('the')
1
"""
# replace pass below with your code
pass

the 1

def syllable_count(word):
"""
Returns the number of syllables in the word.
For this exercise, assume that syllables are determined as follows:
Each sequence of vowels a e i o u y, except for the last e in a word, is a vowel.
However, if that algorithm yields a count of 0, change it to 1.

:param word: the word whose syllables are being counted.

>>> syllable_count('Harry')
2
>>> syllable_count('HAIRY')
2
>>> syllable_count('hare')
1
>>> syllable_count('the')
1
"""
# replace pass below with your code
pass

Explanation / Answer

def syllable_count(word):
syllables=['a','e','i','o','u','y']
last=len(word)
print (last)
count=0
last_word=0
for i in word:
last_word+=1
if i in syllables and last_word!=last :
count+=1
elif i!='e' and i in syllables:
count+=1
if count==0:
count=1
return count;

print(syllable_count('the'))

OUTPUT: 1

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