Public Class frmRectangleArea Dim area As Decimal Dim numberOfRectangles As Inte

Question

Public Class frmRectangleArea     

Dim area As Decimal     

Dim numberOfRectangles As Integer     

Dim smallestRectangle As Decimal = 999999999     

Private Sub btnCalculate_Click(sender As Object, e As EventArgs) Handles btnCalculate.Click         

Dim length As Decimal = CDec(txtLength.Text)         

Dim width As Decimal = CDec(txtWidth.Text)        

area = width * length         

numberOfRectangles = numberOfRectangles + 1         

smallestRectangle = Math.Min(smallestRectangle, area)        

txtArea.Text = area.ToString

txtNumberOfRectangles.Text = numberOfRectangles.ToString        

txtSmallestRectangle.Text = smallestRectangle.ToString        

txtLength.Select()     

End Sub     

Private Sub btnExit_Click(sender As Object,             e As EventArgs) Handles btnExit.Click         

Me.Close()     

End Sub     

Private Sub btnClear_Click(sender As Object, e As EventArgs) Handles btnClear.Click        

numberOfRectangles = 0         

area = 0D         

smallestRectangle = 999999999        

txtLength.Text = ""         

txtWidth.Text = ""         

txtArea.Text = ""         

txtNumberOfRectangles.Text = ""         

txtSmallestRectangle.Text = ""        

txtLength.Select()     

End Sub

End Class

Question. In visual studio, analyzing this code, Comment on why SmallestRectangle is initialized with a large integer rather than 0 and Comment on how the min method works to return the smallest rectangle.

Explanation / Answer

Dim smallestRectangle As Decimal = 999999999

This smallest rectangle variable is initialize with big integer value because in this code to the find the minimum value using the math.min(val1,val2) it will always returns the value which entered by the user if less than 999999999 if user enter value is means area value is greater than 999999999 this value it will return the area value.

Suppose if we pass the value of the Math.Min(999999999,10) it will return the 10 value.

if Math.Min(999999999,10000000000) then it will return the this 10000000000 value.

Math.Min(val1,val2)

In the above syntax val1 and val2 are the two decimal values to find the smallest among them. so it will always return the small value between then.

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