The average tardiness (job lateness) for the sequence developed using the FCFS r

Question

The average tardiness (job lateness) for the sequence developed using the FCFS rule =

days (round your response to two decimal places).

Homework: Chapter 15: Short-Term Scheduling 3 of 5 (5 complete Score: 0.18 of 1 pt Question Help Problem 15.15 a) Using the FCFS first come, first served) decision rule for sequencing the jobs, the order is (assume that jobs came in the order inThe following jobs are waiting to be processed at the same machine center. Jobs are logged as they arrve which they are listed in the table) Duration (days) Due Date 313 312 325 314 315 Job 16 40 Al dates are specified as manufacturing planning calendar days Assume that all jobs arrive on day 275. Assume each jab starts at the baginning af tha day and finishes at the end of the day (a job that hegins on day 275 and takes8 days will finish an day 282, and the naxt job begins in the moming of day 203). Compute all times based on inibiating work on day 275 The average tard ness job lateness) for the sequence devel ped using the FCFS rul: days (round your response to two dscimal places)

Explanation / Answer

Completion time of job A = 275+8-1 = 282

Completion time of Job B = 282+16 = 298

Completion time of Job C = 298+40 = 338

Completion time of Job D = 338+5 = 343

Completion time of Job E = 343 + 3 = 346

Tardiness of Job A = Max(0,282-313) = 0

Tardiness of Job B = Max(0,298-312) = 0

Tardiness of Job C = Max(0,338-325) = 13

Tardiness of Job D = Max(0,343-314) = 29

Tardiness of Job E = Max(0,346-315) = 31

Average Tardiness = (0+0+13+29+31)/5 = 14.60 days

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