Java Part 1: Answer options: O(1), O(n), O(n^2) ---------------------- Part 2: A
ID: 3599215 • Letter: J
Question
Java
Part 1:
Answer options: O(1), O(n), O(n^2)
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Part 2:
Answer options: O(1), O(n), O(n^2)
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Part 3:
Answer options: O(1), O(n), O(n^2)
What is the order of growth of the following operations for lists implemented with arrays? add to the beginning of a list Choose] add to the end of a list [Choose] delete from the beginning or middle of a listChoose] delete from the end of a list [Choose] determine if the list contains an element [Choose] retrieve an element at a specific positionExplanation / Answer
Part 1:
1. O(n) in case of ArrayList because it would require to shift all the existing elements by one position. O(1) in case of linked list.
2. O(1) in both ArrayList and Linked List.
3. O(n) in case of ArrayList because it would require to shift all the existing elements by one position. O(1) in case of LinkedList
4. O(1) in both ArrayList and LinkedList
5. O(1) in ArrayList and O(n) in LinkedList
6. O(1) in ArrayList and O(n) in LinkedList
Part 2:
1. O(1)
2. O(n)
3. O(1)
4. O(n)
5. O(n)
6. O(n)
Part 3:
1. O(1)
2. O(1)
3. O(1)
4. O(1)
5. O(n)
6. O(n)
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