A company Bit-by-Bit Inc. has been assigned a network IP address of 200.108.18.0

Question

A company Bit-by-Bit Inc. has been assigned a network IP address of 200.108.18.0. It has three divisions that need a total of 27 subnets. You are the network administrator for the company and are responsible for creating the subnets.

Please indicate the following four details for the first three subnets and last possible subnet in the network

-Subnet Address (Decimal Format Only)

-Range of host addresses that can be assigned to a host device. (Decimal Format Only)

-Direct broadcast address (Decimal Format Only)

Explanation / Answer

Answer:-

We know that 5 bits are desired for subnets. So, in the last octet (8 bits) of the IP address, first 5 bits are for subnet and 3 are for hosts.

Subnet Number Subnet Address:-

To compute the first subnet id we put 00001000 in the last octet of network IP address. We cannot put 00000 for the first subnet and 11111 for the last as both are reserved. So we subtracted 2 while computing the number of subnets overhead.

=>200.108.18.00001000(replaced first 5 bits with 00001)

=>200.108.18.8(First subnet in Decimal)

Range of host addresses:-

The range of host addresses-->No of host bits is 3.

So 001 will be first assignable host address and 110 will be last. 000 and 111 can be used as they will be used for subnet id and direct broadcast id.

For the first subnet, no of hosts will be-

=>200.108.18.00001001 to 200.108.00001110(Last 3 host bits 001 to 110)

=>200.108.18.9 to 200.108.14(Range of host addresses can be assigned in the first subnet.)

Direct broadcast address:-

To compute DBA of the first subnet, make all host bit 1.

First subnet- 200.108.18.00001111

=>200.108.18.15(DBA of first subnet)

Similarly 2nd, 3rd and last subnet address and details can be considered.

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