1. According to ARIN, the University of Maryland owns the IP block from 128.8.0.
ID: 3601776 • Letter: 1
Question
1. According to ARIN, the University of Maryland owns the IP block from 128.8.0.0 - 128.8.255.255.
a) How many different IP addresses does this block contain?
b) How is this subnet described using CIDR?
c) What would the netmask of this subnet be?
2. A possible IP address in the University of Maryland is 129.2.101.23.
a) Convert this IP address in dotted-decimal notation to a 32-bit number in base-10.
b) List seven different CIDR-ized subnets to which this IP address could belong.
c) For each of the seven different CIDR-ized subnets, you listed, provide their netmasks in dotted-decimal notation.
Please Help. Thank you so much!
Explanation / Answer
Question 1
a) The number of different IP addresses that the block contains is 256*256= 65536.But out of this 65536 IP addresses , two are reserved (1 for Network ID , 1 for Broadcast ID).Hence, effective number of IP addresses is 65536-2=65534.
b) The subnet can be described using the following CIDR notation : 128.8.0.0/16
c) The netmask of this subnet is 255.255.0.0
Question 2
4227072 + 2048 + 3232 + 23 = 4232375
b)&c)
CIDR-ized subnet
Masks
129.2.0.0/16
255.255.0.0
129.0.0.0/8
255.0.0.0
129.2.101.0/24
255.255.255.0
129.2.0.0/15
255.254.0.0
129.2.0.0/14
255.252.0.0
129.2.0.0/13
255.248.0.0
129.2.0.0/12
255.240.0.0
CIDR-ized subnet
Masks
129.2.0.0/16
255.255.0.0
129.0.0.0/8
255.0.0.0
129.2.101.0/24
255.255.255.0
129.2.0.0/15
255.254.0.0
129.2.0.0/14
255.252.0.0
129.2.0.0/13
255.248.0.0
129.2.0.0/12
255.240.0.0
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