Need b,c,e,f,i Computer Logie Design Oetober 27, 2017 R. Kasturi Duration: 75 Mi

Question

Need b,c,e,f,i Computer Logie Design Oetober 27, 2017 R. Kasturi Duration: 75 Minutes Closed Book, Notes, HW CDA 3201 Conflict Exam I on front and back is allowed. One sheet of Letter size paper written SHOW ALL WORK TO GET PARTIAL CREDIT. MAKE REASONABLLE I (One point each) Answer True or False. Unless otherwise noted, all numbers are in decimal. a. The minimized Boolean expression obtained from Quine McCluskey method must include every variable in its true or complement form. The range ofdecimal numbers that can be represented in 8-bit Twos-Complement form is -128 to +128 b. Fd. A truth table implemented by its Canonical Product of Sums form must have the same number of literals as its Canonical Sum of Products implementation. e. The Quine McCluskey method for simplifying a two level function is guaranteed to find a solution that is as good as K-Map method. f As the voltage across a capacitor increases the charge stored in it increases. g Ifa Boolean expression is false its dual must also be false. _ h. F(AB, C)s m(1,3,6) + d(0,2) and M (4,5,7). 110 (0,2) have identical truth tables The sign-magnitude representations of a positive number N and its negative value (-N) di only in one bit. i. Fj An N-Channel MOS transistor forms a conducting channel when its gate is negative with respect to its source.

Explanation / Answer

Answer is as follows:

b) The statement is True that the range of the decimals numbers represented in 8 bit 2's complement has -128 to + 128.

For e.g. the +127 = 01111111 in binary and it's 2's complement is 00000001 that is lies b/w -128 to +128 so we must say that given statement is true.

c) (PQ+(RS)')' = (S(P'R+Q'R))'

By minimize (S(P'R+Q'R))' we get (SR+(PQ)')'

i.e. not eqaul so given statement is false.

e) No it is false, the two level simplification is same as the k map in qm technique. It works for large number of variables.

f) The given statement is true.

i) The Statement is true that there is only one bit difference in signed and unsigned bit. for signed bit it is 1 and for unsigned it is 0.

if there is any query please ask in comments....

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