(c.) What is an assembler language and what are the advantages of using one in c
ID: 3604433 • Letter: #
Question
(c.) What is an assembler language and what are the advantages of using one in comparison to machine code? (6 marks) (d.)The Little Man model of a computer system uses a single-digit op-code and 2-digit memory addressing and has the following instructions defined where the address portion is shown as Op. Code Description 1xx 2xx Add value in memory to accumulator Subtract value in memo Store accumulator value to memo Load value in memory to accumulator Branch to memory location Branch on positive to memory location Branch on negative to memory location Input from In-tray to accumulator Output to out-tray from accumulator Halt ry from accumulator 5xx 6xx 7xx 8xx 901 902 0xx Write a program using the above machine code to read 2 numbers which are input to the in- basket, and display the difference between them as a positive number in the out-basket. Comment every instruction. (12 marks)Explanation / Answer
c) An Assembler language is a low-level programming language for a computer, or other programmable device, in which there is a very strong correspondence between the language and the architecture's machine code instructions. Each assembly language is specific to a particular computer architecture. Assembly language is converted into executable machine code by a utility program referred to as an assembler.
Advantages:
1)Assembly language is more human-readable than machine language
2)Easier to Modify – Assembly language programs are easier for people to modify than machine language programs. This is mainly because they are easier to understand and hence it is easier to locate, correct, and modify instructions, when desired.
3)Easy to Locate and Correct Errors – While writing programs in assembly language, fewer errors are made, and those that are easier to find and correct because on the use of mnemonics and symbolic field names.
d)
00 901 IN read 1st number from in basket and store it into calculator
01 310 STO 10 store content of calculator (1st number) into mailbox 10
02 901 IN read 2nd number from in basket and store it into calculator
03 311 STO 11 store content of calculator (2nd number) into mailbox 11
04 210 SUB 10 calculator = calculator - number in mailbox 10 (2nd – 1st number)
05 808 BRP 08 if result is positive, already got the positive difference, so just output
06 510 LDA 10 load content of mailbox 10 into calculator (1st number)
07 211 SUB 11 calculator = calculator - number in mailbox 11 (1st – 2nd number)
08 902 OUT write content of calculator and put it in the out basket (difference)
09 000 HLT end execution
10 DAT mailbox contain data (first number)
11 DAT mailbox contain data (second number)
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