Name: IPv4 Subnetting For the following exercises, come up with the subnet addre

Question

Name: IPv4 Subnetting For the following exercises, come up with the subnet address, broadcast address, the number of possible hosts, and the first and last valid host address of that subnet. Example l 172.16.37.186/26Subnet Mask 255.255.255.192 Subnet Address 172.16.37.128 Broadcast Address 172.16.37.191 Number of Hosts 62 First Host Address 172.16.37.129 Last Host Address 172.16.37.190 Questions: 192.168.92.157/29lSubnet Mask Subnet Address Broadcast Address Number of Hosts First Host Address Last Host Address 162.29.10.56/21 Subnet Mask Subnet Address Broadcast Address Number of Hosts First Host Address Last Host Address 10.130.109.105/14 Subnet Mask Subnet Address Broadcast Address Number of Hosts First Host Address Last Host Address

Explanation / Answer

1)
    Subnet Mask

      Here /29 means 1st 29 bits are dedicated for Network id

      and the rest 3 bits are for host id.

      Hence Subnet Mask is 11111111.11111111.11111111.11111000

      which is 255.255.255.248

    Subnet Address

      Perform an And Opeation between Subnet Mask and

      given IP address then we will get Subnet Address.

      Given Ip is 192.168.92.157 AND 255.255.255.248

      which is 192.168.92.152

   Broadcast Address

       Here the subnet Address is 192.168.92.152

       which is 192.168.92.10011000.

       Broadcasting means all host bits has to be 1

       and hence broadcast address is 192.168.92.1001111

       which is 192.168.92.159

    Number of Hosts

        Here Number of Hosts is = 2Number of bits for host - 2
                        
                                            = 23 - 2 = 8 - 2 = 6

    First Host Address

       192.168.92.10011001 = 192.168.92.153

    Last Host Address

       192.168.92.10011110 = 192.168.92.158

2)
    Subnet Mask

      Here /21 means 1st 21 bits are dedicated for Network id

      and the rest 11 bits are for host id.

      Hence Subnet Mask is 11111111.11111111.11111000.00000000

      which is 255.255.248.0

    Subnet Address

      Perform an And Opeation between Subnet Mask and

      given IP address then we will get Subnet Address.

      Given Ip is 162.29.10.56 AND 255.255.248.0

      which is 162.29.8.0

   Broadcast Address

       Here the subnet Address is 162.29.8.0

       which is 162.29.00001000.00000000.

       Broadcasting means all host bits has to be 1

       and hence broadcast address is 162.29.00001111.11111111

       which is 162.29.15.255

    Number of Hosts

        Here Number of Hosts is = 2Number of bits for host - 2
                        
                                            = 211 - 2 = 2048 - 2 = 2046

    First Host Address

       162.29.00001000.00000001 = 162.29.8.1  

    Last Host Address

       162.29.00001111.11111110 = 162.29.15.254

3)
    Subnet Mask

      Here /14 means 1st 14 bits are dedicated for Network id

      and the rest 18 bits are for host id.

      Hence Subnet Mask is 11111111.11111100.00000000.00000000

      which is 255.248.0.0

    Subnet Address

      Perform an And Opeation between Subnet Mask and

      given IP address then we will get Subnet Address.

      Given Ip is 10.130.109.105 AND 255.248.0.0

      which is 10.128.0.0

   Broadcast Address

       Here the subnet Address is 10.128.0.0

       which is 10.10000000.00000000.00000000.

       Broadcasting means all host bits has to be 1

       and hence broadcast address is 10.10000011.11111111.11111111

       which is 10.131.255.255

    Number of Hosts

        Here Number of Hosts is = 2Number of bits for host - 2
                        
                                            = 218 - 2 = 262144 - 2 = 262142

    First Host Address

       10.10000000.00000000.00000001 = 10.128.0.1  

    Last Host Address

       10.10000011.11111111.11111110 = 10.131.255.254

4)
    Prefix Length

      Given Subnet Mask is 255.255.224.0 which is

      11111111.11111111.11100000.00000000 in binary

       Here Number of 1's is = prefix length = 19

    Subnet Address

      Perform an And Opeation between Subnet Mask and

      given IP address then we will get Subnet Address.

      Given Ip is 172.54.50.112 AND 255.255.224.0

      which is 172.54.32.0

   Broadcast Address

       Here the subnet Address is 172.54.32.0

       which is 172.54.00100000.00000000.

       Broadcasting means all host bits has to be 1

       and hence broadcast address is 172.54.00111111.11111111

       which is 172.54.63.255

    Number of Hosts

        Here Number of Hosts is = 2Number of bits for host - 2
                        
                                            = 213 - 2 = 8192 - 2 = 8190

    First Host Address

       172.54.00100000.00000001 = 172.54.32.1

    Last Host Address

       172.54.00111111.11111110 = 172.54.63.254

5)
    Prefix Length

      Given Subnet Mask is 255.255.255.128 which is

      11111111.11111111.11111111.10000000 in binary

       Here Number of 1's is = prefix length = 25

    Subnet Address

      Perform an And Opeation between Subnet Mask and

      given IP address then we will get Subnet Address.

      Given Ip is 205.17.60.158 AND 255.255.255.128

      which is 205.17.60.128

   Broadcast Address

       Here the subnet Address is 205.17.60.128

       which is 205.17.60.10000000.

       Broadcasting means all host bits has to be 1

       and hence broadcast address is 205.17.60.11111111

       which is 205.17.60.255

    Number of Hosts

        Here Number of Hosts is = 2Number of bits for host - 2
                        
                                            = 27 - 2 = 128 - 2 = 126

    First Host Address

       205.17.60.10000001 = 205.17.60.129

    Last Host Address

       205.17.60.11111110 = 205.17.60.254

6)
    Prefix Length

      Given Subnet Mask is 255.240.0.0 which is

      11111111.11110000.00000000.00000000 in binary

       Here Number of 1's is = prefix length = 12

    Subnet Address

      Perform an And Opeation between Subnet Mask and

      given IP address then we will get Subnet Address.

      Given Ip is 10.10.171.80 AND 255.240.0.0

      which is 10.0.0.0

   Broadcast Address

       Here the subnet Address is 10.0.0.0

       which is 10.00000000.00000000.00000000.

       Broadcasting means all host bits has to be 1

       and hence broadcast address is 10.00001111.11111111.11111111

       which is 10.15.255.255

    Number of Hosts

        Here Number of Hosts is = 2Number of bits for host - 2
                        
                                            = 220 - 2 = 1048576 - 2 = 1048574

    First Host Address

       10.00000000.00000000.00000001 = 10.0.0.1

    Last Host Address

       10.00001111.11111111.11111110 = 10.15.255.254

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