Question No.1 For each Term/Expression infirst column (labeled “Column-1”), find
ID: 3608483 • Letter: Q
Question
Question No.1
For each Term/Expression infirst column (labeled “Column-1”), find the appropriateTerm from column three (labeled “Column-3”) and writethe answer in second column (labeled“Answer”)
Column-1
Answer
Column-3
Multiplexer
Flip-Flop
A=B.C
Boolean Expression Language
Counter
8-Bits
ABEL
OR-Gate
Byte
Column Address Strobe
Volatile
AND-Gate
CAS
De-Multiplexer
B=C+D
RAM
Question No. 2
Calculate the number of bytes in “32K X 8”memory chip.
Column-1
Answer
Column-3
Multiplexer
Flip-Flop
A=B.C
Boolean Expression Language
Counter
8-Bits
ABEL
OR-Gate
Byte
Column Address Strobe
Volatile
AND-Gate
CAS
De-Multiplexer
B=C+D
RAM
Explanation / Answer
Dear, Question No. 1 Question No. 1 Column-1 Answer Column-3 Multiplexer De-Multiplexer Flip-Flop A=B.C AND-Gate Boolean Expression Language Counter Flip-Flop 8-Bits ABEL Boolean Expression Language OR-Gate Byte 8-Bits Column Address Strobe Volatile RAM AND-Gate CAS Column Address Strobe De-Multiplexer B=C+D OR-Gate RAM Column-1 Answer Column-3 Multiplexer De-Multiplexer Flip-Flop A=B.C AND-Gate Boolean Expression Language Counter Flip-Flop 8-Bits ABEL Boolean Expression Language OR-Gate Byte 8-Bits Column Address Strobe Volatile RAM AND-Gate CAS Column Address Strobe De-Multiplexer B=C+D OR-Gate RAMQuestion No. 2 Numberof bytes = 32K X 8 = 32 X 1024 X 8 = 262144Bytes I hope this will helpfulfor you........... Column-1 Answer Column-3 Multiplexer De-Multiplexer Flip-Flop A=B.C AND-Gate Boolean Expression Language Counter Flip-Flop 8-Bits ABEL Boolean Expression Language OR-Gate Byte 8-Bits Column Address Strobe Volatile RAM AND-Gate CAS Column Address Strobe De-Multiplexer B=C+D OR-Gate RAM
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