Assume an 8th bit, b subscript 7, serving as an even parity bit isadded to the 7
ID: 3608664 • Letter: A
Question
Assume an 8th bit, b subscript 7, serving as an even parity bit isadded to the 7-bit ASCII code. Give the coded representation foreach of the following character strings as hexadecimal numbers:Z = 1
Please help, I don't understand this question. I have a vagueidea of what to do. This is what i have so far, not sure ifcorrect:
5A203D201 as the hexadecimal equivalent
but I do not know what to do form here on. The required text(which is not in my possession) is terrible.
Please explain this question and show me how to do thisproblem. Thanks.
Z = 1
Please help, I don't understand this question. I have a vagueidea of what to do. This is what i have so far, not sure ifcorrect:
5A203D201 as the hexadecimal equivalent
but I do not know what to do form here on. The required text(which is not in my possession) is terrible.
Please explain this question and show me how to do thisproblem. Thanks.
Explanation / Answer
Dear, Z = 1 , will not be 5A203D2 01(It will be 31 according to u, asscii value of 1 =(31)16, because this is just a ascii conversion,you will need to insert the parity bit. Z => 5A => (1011010)2 the number of 1's are even so we will insert 0 at 8th bit. so it will be (01011010)2 5A " " => 20 =>(100000)2 since number of 1 is odd, so 1 will be inserted at 8thbit. so it will be (10100000)2 =>A0 = => 3d => 111101 no of 1 is odd so to make it even we will insert 1 at8th bit. 10111101 =>BD 1 => 31 => 110001 to make 1's even, 1 will be inserted at 8th bit. 10110001 = B1 so final value will be 50 A0 BD A0 B1
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