Consider the following three machine instructions, whichappear in memory startin

Question

Consider the following three machine instructions, whichappear in memory starting at the address 0x00400000. address (in hex) contents (in hex) 0x00400000 0x12080002 0x00400004 0x3C11FFFF 0x00400008 0x08100004

(a) Disassemble" the instructions; that is, give an assemblylanguage program segment that would be translated into the given machinelanguage.
(b) You may use numeric rather than symbolic registernames.
(c) Handle branches and jumps specially; where you wouldnormally have a label, provide instead a hexadecimal byte address.

these question are very confusing for me. Greatlyappreciated! Confused with the whole address stuff. pleasehelp. Consider the following three machine instructions, whichappear in memory starting at the address 0x00400000. address (in hex) contents (in hex) 0x00400000 0x12080002 0x00400004 0x3C11FFFF 0x00400008 0x08100004

(a) Disassemble" the instructions; that is, give an assemblylanguage program segment that would be translated into the given machinelanguage.
(b) You may use numeric rather than symbolic registernames.
(c) Handle branches and jumps specially; where you wouldnormally have a label, provide instead a hexadecimal byte address.

these question are very confusing for me. Greatlyappreciated! Confused with the whole address stuff. pleasehelp.

Explanation / Answer

Dear,    Given inatructions are,    Contents               Address 0x12080002         0x00400000   0x3C11FFFF      0x00400004   0x08100004        0x00400008 For the given hexa instruction the equivalent machinecode is,          0x12080002   - Incerement Index Register INX and store theresultant value in the address location 0x00400000          0x3C11FFFF -The value in the stored index register is compared with accumlatorand the result is stored in the address location 0x00400004                                    Themachine instructions are, CBA and STX             0x08100004 -Now the Accumlator is incremented and stored in address location0x00400008                                     Themachine instructions are, INX " I hope this will help you "   0x3C11FFFF      0x00400004   0x08100004        0x00400008 For the given hexa instruction the equivalent machinecode is,          0x12080002   - Incerement Index Register INX and store theresultant value in the address location 0x00400000          0x3C11FFFF -The value in the stored index register is compared with accumlatorand the result is stored in the address location 0x00400004                                    Themachine instructions are, CBA and STX             0x08100004 -Now the Accumlator is incremented and stored in address location0x00400008                                     Themachine instructions are, INX " I hope this will help you "

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