I want to write a program that takes the factorial of aninteger and has the foll

Question

I want to write a program that takes the factorial of aninteger and has the following cases: 1 - if there is no inputparameters, output (" No inputs"). 2 - if there are two ormore command line parameters , the program gives (" Only onenumber"). 3 - The command lineparameter must be an 8 bit unsigned integer, if not the outputmust be
"ERROR 8-Bit". 4 - Given an integer nthe output should be the result of the calculation n!. All calculations should be done using a standard signed integer (32 bit) and the result printed out .The printout shall be aninteger with no "e" notation, for example 6e4 would not be avalid output.
5- If the calculation proves impossible the output should be"Impossible to calculate". please I want the codes with explainations . . . I want to write a program that takes the factorial of aninteger and has the following cases: 1 - if there is no inputparameters, output (" No inputs"). 2 - if there are two ormore command line parameters , the program gives (" Only onenumber"). 3 - The command lineparameter must be an 8 bit unsigned integer, if not the outputmust be
"ERROR 8-Bit". 4 - Given an integer nthe output should be the result of the calculation n!. All calculations should be done using a standard signed integer (32 bit) and the result printed out .The printout shall be aninteger with no "e" notation, for example 6e4 would not be avalid output.
5- If the calculation proves impossible the output should be"Impossible to calculate". please I want the codes with explainations . . . please I want the codes with explainations . . .

Explanation / Answer

please rate - thanks #include using namespace std; int main(int argc, char * argv[]) {intnum;             int factorial=1,i=1,previous=0;    //start factorialat multiplicative identity                                   //previous is previous value of factorial if(argc==1)                       //argc tells us how many arguments there are     cout

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