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Suppose that the logical address space of a process consist of32 pages and each

ID: 3612233 • Letter: S

Question

Suppose that the logical address space of a process consist of32 pages and each page consist of 2 bytes. The main memory consistsof 32 frames and the size of each frame is also 2 bytes. Calculatethe following from the given information:

a)      Calculate the size of logicaladdress space of the process?

b)      Calculate the physical addressspace of the main memory?

c)      Calculate the no. of bitsrequired for the Page Number ‘p’?

d)      Calculate the no. of bitsrequired for offset ‘d’?

e)      Find the number of entries inthe page table?

Explanation / Answer

Dear User,       a) The size of thelogical address space of the process = 32 x 2 bytes                                                                                         = 64 bytes                                                                                                                                =26 x 23                                                                                          =29                                                                                        m = 9 bits                                                                                        m = 9 bits                             b) The size of thephysical address space of the main memory = 32 x 2 bytes                                                                                                    = 64 bytes                c) The number of bits requiredfor the page number P = m- n bits = 9 - 4 =5 bits                                                                 pagesize = 2 bytes = 21 x 23 = 24                                                                         So, n=4 bits        d) The number ofbits required for offset (d) = n=4 bits        e) The number ofentries in the page table = number of pages = 32 I hope this will helps toyou                                                                         So, n=4 bits        d) The number ofbits required for offset (d) = n=4 bits        e) The number ofentries in the page table = number of pages = 32 I hope this will helps toyou
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