Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

roblem 12.52 - Question Help | * Henrique Correa\'s bakery prepares all its cake

ID: 361306 • Letter: R

Question

roblem 12.52 - Question Help | * Henrique Correa's bakery prepares all its cakes between 4 A.M.and 6 A.M.so they will be fresh when customers arrive. Day-old cakes are virtually always sold, but at a 50% discount off the regular $16 price. The cost of baking a cake is $10, and demand is estimated to be normally distributed, with a mean of 25 and a standard deviation of 7. What is the optimal stocking level? Refer to the standard normal table for z-values. The optimal stocking level for the bakery is cakes (round your response to the nearest whole number).

Explanation / Answer

This problem will be solved using Newsvendor model

Given are following data :

Average demand = m = 25

Standard deviation of demand = Sd = 7

Sale price = P = $16/ unit

Cost of cake = C = $10 / unit

Salvage price = S = 50% of $16 = $8 / unit

Thus ,

Cost of underordering = Cu = P – C = $16 - $10 = $6 / unit

Cost of overordering = Co = C – S = $ 10 - $ 8 = $ 2/ unit

Therefore,

Critical ratio = Cu/ ( Cu + Co) = 6/ ( 6 + 2) = 6/8 = 0.75

Critical ratio is the probability of optimum stocking level . Corresponding Z value for such optimum stocking level = NORMSINV ( 0.75 ) = 0.6745

Therefore , Optimum stocking level for the Bakery

= m + Z x Sd

= 25 + 0.6745x 7

= 25 + 4.72

= 29.72 ( 30 rounding to next higher whole number )

OPTIMUM STOCKING LEVEL FOR THE BAKERY = 30

OPTIMUM STOCKING LEVEL FOR THE BAKERY = 30