/* This program takes thenatural logarithm of an input number */ #include<stdio.

Question

/* This program takes thenatural logarithm of an input number */

#include<stdio.h>
#include <stdlib.h>
#include <math.h>

int main(void)
{
    double n;
int i;
for(i=0;i<2;i++)
printf("Enter a number whose natural log you want to find:");
scanf("lf", &n);
if(n<=0)
       {if(i==0)
          Printf("Invalid entry-Only 2 attemps allowed ");
       else if(i==1)
          printf("I warned you-You-you incompetent--I'm out ofhere!!! ");
           }
  
   else
   {
       printf("The natural log of"<<n<<" is "<<log(n)<<endl);
      i=2;   //instead of usinga break to exit the loop
      }
}
system("pause");

return 0;
}  

Explanation / Answer

/* This program takes the natural logarithm of an input number*/ #include #include #include #include int main(void) {     double n; int i; for(i=0;i

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