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#include <stdio.h> void bin (int num) //the bin commandturns every byte in the i

ID: 3614384 • Letter: #

Question

#include <stdio.h>


void bin (int num) //the bin commandturns every byte in the input into its binary representation

{

while (num != 0)

{

printf("%i", num % 2); //the modulusoperator returns the remainder of the number divided by base 2

num = num/2; //number divided by base2

}

printf(" ");

}


intmain(void){

intnum;

printf(" Please enter an integer number to be converted:");

scanf("%i", &num); //user entersnumber

printf(" ");


bin(num); //bin function call

printf(" ");

return 0;


}

Explanation / Answer

please rate - thanks to keep your algorithm arrays must be used since the digits aregenerated in reverse it can also be done with a mask and shifting I made the array 8 since your comment talks about bytes and 8 bitsper byte #include void bin (int num) //the bin command turns every byte in the inputinto its binary representation { int val[8],i,n=0; while (num != 0) { val[n++]=num%2; //printf("%i", num % 2); //the modulus operator returns theremainder of the number divided by base 2 num = num/2; //number divided by base 2 } for(i=n-1;i>=0;i--) printf("%d",val[i]); printf(" "); } int main(void){ int num; printf(" Please enter an integer number to be converted:"); scanf("%i", &num); //user enters number printf(" "); bin(num); //bin function call printf(" "); return 0; }

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