There are 50 employees in an organization Create a “struct” called “employee” to

Question

• There are 50 employees in an organization
• Create a “struct” called “employee” tohold the following employee records
• • Employee ID (0 to 49)
  • Employee Salary (2500 to 3500)
  • Employee Status (F or P)
• struct will create a user-defined data-type for employeeinformation
• All the 50 employee’s record should have the samedata-type of “struct employee”
• • Hint: Create a employee array of type“employee”
• Randomly fill the salary and status values for all employees(using looping)

• Ask user to enter a number between 0 to 49, say X
• Print the employee X’s information

Explanation / Answer

using namespace std;
struct employee { int id; int salary; char status; }; int main() { employee array[50]; for(short v=0;v<50;v++) { cout<<"Please enter the Id of Employee"; cin>>array[v].id; cout<<"Please enter the Salary of Employee"; cin>>array[v].salary; cout<<"Please enter the status of Employee"; cin>>array[v].status; } int x; cout<<"Enter a number to display his Record"; cin>>x; if(x<50) { cout<<" Employee ID:"<<array[x].id; cout<<" EmployeeSalaray:"<<array[x].salary; cout<<" Employee Status:"<<array[x].status; } else cout<<"Employee is Not exist for this number"; system("pause"); return 0; }

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