/* In-class #5: Write a C++ program that converts between money value and its co

Question

/*

In-class #5:

Write a C++ program that converts between money value and its coin equivalence.

If coin to money is desired, it asks for coin value and converts them to money value;

Otherwise, if money to coin is desired, it asks for money value and converts to its

coin equivalence. Coin type is limited to quarter, dime, nickel, and penny. And

coin equivalence is restricted to the least amount of coins. Use setw to format the output

as shown in the sample output.

Note:

Input/output is listed as coin to money. For money to coin, just flip input and output

INPUT INFO conversion type - c for coin to money, m for money to coin

number of quarters - numQ - no decimal

number of dime, - numD - no decimal

number of nickes - numN - no decimal

number of pennies - numP - no decimal

OUTPUT INFO money value, in dollar - moneyValue - real number

CONSTANTS as cents: QUARTER = 25

DIME = 10

NICKEL = 5

DOLLAR = 100

CONSTRAINTS 1. coin equivalence to be the least amount of coins

2. format the output as a chart as following:

Coin Money Conversion

Moneytary Amount Dollar(s) Quarter(s) Dime(s) Nickel(s) Penny(s)

1.33 1 1 0 1 3

OPERATIONS

1. Display a menu to get user choice: c for coin to money, m for money to coin

2. Get user choice

3. If user chooses m then

3a. Prompt and get money value

3b. Determine number of dollar bills --- you figure out how

3c. convert left over to total pennies, as int, round off --- you figure out how

3d. numQ is integral part of totalPenny / QUARTER

3e. remainder = totalPenny - numQ * QUARTER

3f. numD is integral part of remainder / DIME

3g. remainder = remainder - numD * DIME

3h. numN = remainder / NICKEL

3i. numP = left over after nickel

4. Else if user choose c then

--- you fill up the steps

5. Either way, display the result

*/

#include

#include

using

// global constants are declared above main

const

DIME = 10,

NICKEL = 5,

DOLLAR = 100;

int

{

numD,

numN,

numP,

remainder,

totalPenny,

dollars;

cout <<

<<

<<

<<

cin >> type;

{

cout <<

cin >> moneyValue;

dollars =

numQ = totalPenny / QUARTER;

remainder = totalPenny % QUARTER;

numD = remainder / DIME;

remainder %= DIME;

numN = remainder / NICKEL;

numP = remainder % NICKEL;

}

{

}

system(

}

Explanation / Answer

please rate - thanks #include #include using namespace std; // global constants are declared above main const int QUARTER = 25, DIME = 10, NICKEL = 5, DOLLAR = 100; int main() { // items in input and output are declared as variables // variables are declared within a function char type; // for conversion type, c for coin to money, m for moneyto coin int numQ, numD, numN, numP, remainder, // used to store left over values totalPenny, // needed for intermidiate result dollars; double moneyValue; // step 1-2 cout moneyValue; dollars = static_cast(moneyValue); totalPenny=(moneyValue-dollars)*100+.005; numQ = totalPenny / QUARTER; remainder = totalPenny % QUARTER; numD = remainder / DIME; remainder %= DIME; numN = remainder / NICKEL; numP = remainder % NICKEL; } // step 4, convert coin to money // code according to your spec; place the code inside the block else if(type == 'c') {coutdollars; coutnumQ; coutnumD; coutnumN; coutnumP; moneyValue=(dollars*100+numQ*25+numD*10+numN*5+numP)/100.; // put your code in this block } // step 5, display result goes below this line cout

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