Given the array declaration, int a[20], the last (legal)element is written as __

Question

Given the array declaration, int a[20], the last (legal)element is written as _____. A)a[2]
B)a[0]
C)a
D)a[20]
E)a[19]
Are the following array initializations correct? If not, whynot? A)int x[4] = {8, 7, 6, 5, 4}
B)int x[] = {8, 7, 6, 5, 4}
C)int x[2] = {8, 7, 6};
D)const int SIZE =4 int x[SIZE]
E)const int SIZE =4 int x[SIZE-4] Given the array declaration, int a[20], the last (legal)element is written as _____. A)a[2]
B)a[0]
C)a
D)a[20]
E)a[19]
Given the array declaration, int a[20], the last (legal)element is written as _____. Are the following array initializations correct? If not, whynot? A)int x[4] = {8, 7, 6, 5, 4}
B)int x[] = {8, 7, 6, 5, 4}
C)int x[2] = {8, 7, 6};
D)const int SIZE =4 int x[SIZE]
E)const int SIZE =4 int x[SIZE-4] Are the following array initializations correct? If not, whynot? A)int x[4] = {8, 7, 6, 5, 4}
B)int x[] = {8, 7, 6, 5, 4}
C)int x[2] = {8, 7, 6};
D)const int SIZE =4 int x[SIZE]
E)const int SIZE =4 int x[SIZE-4] Are the following array initializations correct? If not, whynot?

Explanation / Answer

1) E is the correct answer     The elements in the array has index 0, 1, 2,3.....SIZE-2, SIZE-1   [therefore the number of elementsin array are SIZE]     AS SIZE= 20 here, the last element would bea[SIZE - 1]                                                                      = a[20-1]                                                                        =a[19] 2) A is wrong since size of array is 4 and initialization has 5elements in the parenthesis B is correct since size was not declared, it will take size as thenumber of elements in the parenthesis     Therefore size of array x will be 5 and it is avalid initialization C is wrong since size of array is 2 and initialization has 3elements in the parenthesis D is correct, here SIZE=4 and it initializes an array withsize=4.i.e. it can hold 4 elements E is not a valid initialization since there cannot be an array with0 size

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