Hello I am in my second year as a college student taking my 2ndclass as a Comput

Question

Hello I am in my second year as a college student taking my 2ndclass as a Computer Science major. In my class we are currentlylearning different ways to use arrays. Below is a series of codesof how to use arrays in different ways. My problem is figuring outthe part of the code where I guess the array is output in reverse(if you understand what I mean its the "public static int[]reverseA(int[] a)" part ). If it helps understanding my code bettermy class writes it from NetBeans IDE 6.7 and we use Java.

please and thank you for your help in advanced

package morearrays;

public class Main {

    public static void printArray(int[] a){
        for (int i = 0; i <a.length; i++ ){
           System.out.println(a[i]);
        }
    }

    public static void copyArray(int[] a){
        int[] a2 = newint[a.length];
        for (int i = 0; i <a2.length; i++) {
           a2[i] = a[i];
        }
        printArray(a2);
    }

    public static void compareArrays(int[] a, int[]b){
        boolean equal =false;
        if(a.length == b.length){ equal = true; }
        int i=0;
        while((i < a.length)&& equal) {
           if(a[i] != b[i]) { equal = false; }
           i++;
        }
        if (equal){System.out.println("they are EQUAL");
        }else {
           System.out.println("they are NOT EQUAL");
        }
    }

    public static void findHL(int[] a){

        int lowest = a[0],highest = a[0], temp =0;
        for (int i = 0; i <a.length; i++) {
           temp = a[i];
           if (temp > highest) { highest = temp; }
           if (temp < lowest) { lowest = temp;}
        }
        System.out.println("high= "+highest+" lowest ="+lowest);
    }

    public static int[] reverseA(int[] a){
        int[] b = newint[a.length];
        int dec =a.length-1;
        for (int i = 0; i <b.length; i++, dec--){
           b[dec] = a[i];
        }
        return b;
    }

    public static void main(String[] args) {
        int[] a1 = {1, 2, 3, 4,5,};
        int[] a2 = newint[a1.length];
       for (int i = 0; i <a2.length; i++){
           a2[i] = a1[i];
        }
       printArray(reverseA(a1));
    }
}

Explanation / Answer

please rate - thanks hope this helps    public static int[] reverseA(int[] a){ //allocate a new array to get the reverseddata         int[] b = newint[a.length]; //dec has 1 less then the number of elements in ain it, since indices are 0 to 1 less then the number ofelements         int dec =a.length-1; //starting at the 1st element of a and the lastelement of b     (I think this is where yourproblem must be) //each iteration i is incremented, so you are going through a0,1,2,3..., at the same time dec is decremented, so you //are going through b backward, dec,dec-1,dec-2...   thusputting a into b backward (reversing thearray)         for(int i = 0; i

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