Use this skeleton for \'main\': int main() { char cstring[81]; cout << \"\ Enter

Question

Use this skeleton for 'main':

int main()

{

char cstring[81];



cout << " Enter a string, 80 or fewer characters: ";

cin.getline(cstring, 81);

cout << " The number of words in that string: ";

cout << wordCount(cstring) << endl << endl;

return 0;

}




Note: The main problem in this exercise istraveling within a string,

character by character, while determining whether we are inside ofa word or in

between words (space). Here is a bit of pseudocode, which shouldhelp get started:



index = 0

while string[index] != NULL



if char = space

while char = space

keep looping

if char = nonspace

word++ //we must be in a word

while char = nonspace

keep looping



index++



endwhile



Notes:

• 
  
  
• The pseudocode above is not a required skeleton; it is onlymeant to
  
  exemplify the concept.
  
  
• 
  
• Also don't forget that a pointer to the string will be used,inside the
  
  wordCount function.
  
  
• 
  
• Be sure to use the function 'isalnum' and 'isspace' forcomparing
  
  characters.
  
  
• 
  
• Anticipate possible multiple spaces in front of the sentence,in between
  
  words, etc.
  
  
• 
  
• When looping inside of a word, be prepared to run into anapostrophy or
  
  other punctuation (ex: don't), therefore, requiring an additionalcondition for
  
  the while loop such as:
  
  
• 
  

while( isalnum(word[index]) || ( ispunct(word[index])) )

From the book:

Average Number of Letters: Modify the program youwrote for problem 3

(Word Counter), so it also displays the average number of lettersin each word.



int main()

{

char cstring[81];



cout << " Enter a string, 80 or fewer characters: ";

cin.getline(cstring, 81);

cout << " The number of words in that string: ";

cout << wordCount(cstring) << endl << endl;

return 0;

}



index = 0

while string[index] != NULL



if char = space

while char = space

keep looping

if char = nonspace

word++ //we must be in a word

while char = nonspace

keep looping



index++



endwhile



Notes:

• 
  
  
• The pseudocode above is not a required skeleton; it is onlymeant to
  
  exemplify the concept.
  
  
• 
  
• Also don't forget that a pointer to the string will be used,inside the
  
  wordCount function.
  
  
• 
  
• Be sure to use the function 'isalnum' and 'isspace' forcomparing
  
  characters.
  
  
• 
  
• Anticipate possible multiple spaces in front of the sentence,in between
  
  words, etc.
  
  
• 
  
• When looping inside of a word, be prepared to run into anapostrophy or
  
  other punctuation (ex: don't), therefore, requiring an additionalcondition for
  
  the while loop such as:
  
  
• 
  

while( isalnum(word[index]) || ( ispunct(word[index])) )







Average Number of Letters: Modify the program youwrote for problem 3

(Word Counter), so it also displays the average number of lettersin each word.

Explanation / Answer

please rate - thanks #include int wordCount(char*,int&); using namespace std;       int main()       {int tot=0,w;       char cstring[81];       cout

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