Time Clock Design a class named TimeClock. The class should be derived from the

Question

Time Clock

Design a class named TimeClock. The class should be derived from the MilTime class you designed in Programming Challenge 1. The class should allow the programmer to pass two times to it: starting time and ending time. The class should have a member function that returns the amount of time elapsed between the two times. For example, if the starting time is 900 hours (9:00 am), and the ending time is 1300 hours (1:00 pm), the elapsed time is 4 hours.
Input Validation: The class should not accept hours greater than 2359 or less than 0.

Explanation / Answer

please rate - thanks you did not provide the class to derive from, so I had to start from scratch
#include<iostream>
#include<iomanip.h>
using namespace std;
void convert(int,int&,int&);
class Time
{
public:
int hour,minute;
Time()                                                //constructor
   {hour=0;
    minute=0;
   }
~Time()                                           //destructor
    {hour=0;
     minute=0;
    }   
Time(int h,int m)
    {hour=h;
     minute=m;
    }
void get()                                                       //get the time from the user
   {cout<<"Enter the time ";
    cout<<"Hour:    ";
    cin>>hour;
    while(hour<0||hour>23)
       {cout<<"Invalid hour ";
        cout<<"Hour:    ";
         cin>>hour;
         }
    cout<<"Minutes: ";
    cin>>minute;
    while(minute<0||minute>59)
       {cout<<"Invalid minute ";
        cout<<"Minutes:    ";
         cin>>minute;
         }
   }
void show()                                        //print the time with 2 characters and 0 fill to make all digits 2, leading 0 if needed
{cout<<setw(2)<<setfill('0')<<hour<<":"<<setw(2)<<setfill('0')<<minute<<endl;
}            
Time operator - ( Time t)                 //overloaded subtraction operator
    {int h,m,totalmin;
     totalmin=(hour*60+minute)-(t.hour*60+t.minute);
     cout<<totalmin<<endl;
     if(totalmin<0)                    //since subtraction if larger # was second the answer will be negative so change to positive
        totalmin=-totalmin;
     convert(totalmin,h,m);    
     return Time(h,m);
    }
void convert(int totalmin,int& h,int& m)
{ m=totalmin%60;           
      h=(totalmin/60)%12;                
     if(h==0&&totalmin>60)                          
       h=12;
     return;
}           
};
   
int main()
{ Time time1,time2,added,subtracted;
cout.setf(ios::fixed,ios::floatfield);
cout.precision(2);
time1.get();                                          //get 1st time
time2.get();                                        //get 2nd time
subtracted=time1-time2;                   //subtract
cout<<"Time 1 : ";                            //do the output nicely
time1.show();
cout<<"Time 2 : ";
time2.show();
cout<<" Subtracted: ";
time1.show();
cout<<"-";
time2.show();
cout<<"---------- ";
subtracted.show();
system("pause");
}

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