Write a C++ program to determine which numbers between 5 and 500 are perfect num

Question

Write a C++ program to determine which numbers between 5 and 500 are perfect numbers. Also, determine which numbers between 10 and 300 are prime numbers. Send your output to a file Inam_nums.out. Design the output as follows:
Perfect Numbers between 5 and 500
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
              6
            28
           etc

Prime Numbers between 10 and 300
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
             11
             13
            etc
Program Requirements:
Use five functions for this program:
// Function prototypes.
void PrintHeading1 ();
void PrintHeading2 ();
bool IsPerfect (int);
bool IsPrime (int);

int main ()
{ .
.
.
return 0;
}

Explanation / Answer

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#include <iostream>
#include <fstream>
using namespace std;
// Function prototypes.
void PrintHeading1 ();
void PrintHeading2 ();
bool IsPerfect (int);
bool IsPrime (int);
ofstream out;
int main()
{out.open("Inam_nums.out");  
PrintHeading1 ();

for(int i=5;i<=500;i++)
    if(IsPerfect (i))
         out<<" "<<i<<endl;
PrintHeading2 ();        
for(int i=10;i<=300;i++)        
     if(IsPrime (i))
          out<<" "<<i<<endl;
       
  
out.close();
return 0;
}
void PrintHeading1 ()
{out<<"Perfect Numbers between 5 and 500 ";
out<<"_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ ";
}
void PrintHeading2 ()
{out<<"Prime Numbers between 10 and 300 ";
out<<"_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ ";
}
bool IsPerfect (int n)
{int i,sum=1;
for(i=2;i<n;i++)
    if(n%i==0)
        sum+=i;
if(sum==n)
   return true;
else
   return false;
}
bool IsPrime (int n)
{int i;
for(i=2;i<n;i++)
   if(n%i==0)               //if you find a factor the number isn't prime
      return false;
return true;                // get here only if no factors
}

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