Create an Employee class with two fields:IDNum and hourlyWage. The Employee cons

ID: 3622707 • Letter: C

Question

Create an Employee class with two fields:IDNum and hourlyWage. The Employee constructor requires values for both fields. Upon construction, throw an ArgumentException is the hourlyWage is lees than 6.00 or more than 50.00. Write a program that establishes, one at a time, at least three Employees with hourlyWages that are above, below, and within the allowed range. Immediately after each instantiation attempt, handle any thrown Exceptions by displaying an error message. Save the file as EmployeeExceptionDemo.cs

Explanation / Answer

Dear, Here is the code using System; namespace ConsoleApplication4 { class EmployeeExceptionDemo { // The main entry point for the application. static void Main(string[] args) { try { Console.WriteLine("Employee 1:"); Employee emp1=new Employee(1432,5.5); Console.WriteLine("Employee 2:"); Employee emp2=new Employee(1432,50.5); Console.WriteLine("Employee 3:"); Employee emp3=new Employee(1832,5.5); } catch (Exception ex) { Console.WriteLine(ex.Message); } } } class Employee { public int idNum; public double hourlyrate; public Employee(int idNumber, double emprate) { idNum = idNumber; if (emprate < 6 || emprate > 50) { throw new ArgumentException("Value does not fall within the expected range."); } else hourlyrate = emprate; } } } Hope this will help you

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Create an Employee class with two fields: IDNum and hourlyWage . The constructor

Create an Employee class. Might look like this: public class Employee { } Add th

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Create an Employee class with two fields:IDNum and hourlyWage. The Employee cons

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