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<p>24. A router has \'the following RIP routing table: <br />&#160;&#160;&#160;&

ID: 3625524 • Letter: #

Question

<p>24. A router has 'the following RIP routing table: <br />&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; &#160;Netl&#160;&#160;&#160;&#160;&#160; &#160;4&#160;&#160;&#160;&#160; B<br />&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; Net2&#160;&#160;&#160;&#160; &#160;2&#160;&#160;&#160;&#160; C<br />&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; Net3&#160;&#160;&#160;&#160;&#160; 1&#160;&#160;&#160;&#160; F<br />&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; Net4&#160;&#160;&#160;&#160;&#160; 5&#160;&#160;&#160; &#160;G<br /><br />What would be the contents of the table if the router received the following RIP message from router C? <br />&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; Netl&#160;&#160;&#160;&#160;&#160;&#160;&#160; 2 <br />&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; Net2&#160;&#160;&#160;&#160;&#160;&#160; 1 <br />&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; Net3&#160;&#160;&#160;&#160;&#160;&#160; 3 <br />&#160;&#160;&#160;&#160;&#160;&#160;&#160;&#160; Net4&#160;&#160;&#160;&#160;&#160;&#160; 7 <br /><br /></p>

Explanation / Answer

a)Net 1 can be reached via c in 2 + 1 steps original is 4 steps .As newer route requires only 3 steps . It is replaced. b)Net 2 can be reached via c in 2 steps ( unchanged ) original = new c)Net 3 can be reached via c in 3 + 1 steps ( unchanged ) original takes 1 step which is less than new route d)Net 4 can be reached via c in 7+1 steps ( unchanges) original takes 5 steps which is less than new route Hence The new routing table is Net1 3 C Net2 2 C Net3 1 F Net4 5 G // Hope this helps . Please rate :)

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