9. Indicates the results after processing the following code: Multiply 4h by 8h
ID: 3626075 • Letter: 9
Question
9. Indicates the results after processing the following code:
Multiply 4h by 8h (unsigned, 8 bits each) (the) result (s) is stored (n) in (the) register (s):
A. AX
B. BX
C. CX
D. DX
10. Indicates the results after processing the following code: Multiply 4h by 8h (no signs, 8bits one):
A. 24h
B. 32h
C. 48h
D. 84h
11. Indicates the results after processing the code below: Multiply 53216h by 2000h (no signs 16bits each) the result is stored in:
A. EAX: EDX
B. ECX:EDX
C. EDX:EAX
D.EDX: ECX
12. Indicates the results after processing the code below: Multiply 43245h by 200h (unsigned, 16 bits each) in the results stored in registers in the previous question as a result of the multiplication are:
A. ECX= 00 00 00 01 EDX= 06 43 20 00
B. EDX= 00 00 00 01 ECX= 06 43 20 00
C. EDX= 00 00 00 01 EAX= 06 43 20 00
D. EAX= 00 00 00 01 EDX= 06 43 20 00
13. Indicates the results after processing the code below: Divide 5004h by 200h (unsigned, 16bits each)
A. Cociente en AX residuo en DX
B. Cociente en DX Residuo en AX
C. Cociente en CX Residuo en DX
D. Coiente en DX Residuo en AX
14. Indicates the results after processing the code below: Divide 5004h by 200h (unsigned, 16bits each) Following this division the quotient (result) and the residue (remainder) is:
A. CX=25 DX=4
B. DX =25 CX=4
C. AX=25 DX=4
D. DX=25 AX=4
15. Carefully evaluated the following alternatives and chooses the assembler programming language that best resembles the code
if(BX<=CX)
X=1
A. cmp bx,cx jh L1 mov x,z L1:-----
B. cmp bx, cx jl L1 mov x,1 L1:---
C. cmp bx, cx je L1 mov x,1 L1:---
D. cmp bx,cx jh L1 mov 1, x L1:----
Explanation / Answer
Dear, 9. A. AX10.B. 32h
13. A. Cociente en AX residuo en DX
14. C. AX=25 DX=4
15. B. cmp bx, cx jl L1 mov x,1 L1:---
Hope this will help you
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