Consider the following functions: int func1(int x) { int r, s; r = 2 * x; if (r

Question

Consider the following functions:

int func1(int x)
{
int r, s;

r = 2 * x;

if (r > 10)
{
s = x / 2;
}
else
{
s = x / 3;
}
return s - 2;
}

int func2(int a, int b)
{
int r, s;

s = 0;
for(r = a; r < b; r++)
{
s++;
}
return s;
}

What is the output from the following program fragments?

int a, b;

a. a = 10;
cout << func1(a) << endl;
b. a = 5; b = 12;
cout << func2(a, b) << endl;
c. a = 8;
b = func1(a);
cout << a << " " << b << " " << func2(a, b) << endl;

Explanation / Answer

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int func1(int x)
{ int r, s; r = 2 * x;
if (r > 10)
     { s = x / 2;
    }
else
   { s = x / 3; }
return s - 2;
}
int func2(int a, int b)
{ int r, s; s = 0;
for(r = a; r < b; r++)
{ s++; }
return s; }
What is the output from the following program fragments?
int a, b;
a. a = 10; cout << func1(a) << endl;
x=10
r=20:r>10 yes   s=10/2=5       

answer is 5

b. a = 5; b = 12; cout << func2(a, b) << endl;  
in func2
a=5, b=12
s=0:
r=5 s=1;
r=6, s=2;

r=7, s=3;r=8, s=4;
r=9, s=5; r=10, s=6
r=11, s=7
r = 12
answer is 7
c. a = 8; b = func1(a); cout << a << " " << b << " " << func2(a, b) << endl;

in func1 x=8
r=16

16>10   s=4
in main b=4

call func2

a=8, b=4

s=0

r=8, never does loop 0 is returned

output is

8 4 0

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