Read a set of positive interger numbers from the keyboard. Count the frequency o

Question

Read a set of positive interger numbers from the keyboard. Count the frequency of "1","2","3". Also count the total number of numbers. Note there may be other numbers in the list. Output your results as follows:

The number of 1s = 9999
The number of 2s = 9999
The number of 3s = 9999
Total number of numbers = 9999

The seminal or flag number will be a negative number. 9999 stands for whatever number you find.
Test your program with following data
1,3,6,8,2,9,2,1,3,6,9,1,2,3,7,9,4,3,5,1,-99

Explanation / Answer

Dear Friend here is the program u want PLEASE RATE #include using namespace std; void main() { int num; int count[4]={0}; cin>>num; while(num>0) { (count[0])++; if(num==1) (count[1])++; else if(num==2) (count[2])++; else if(num==3) (count[3])++; cin>>num; } cout

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