Write an applacation that demonstrates that when two identical names are compare

Question

Write an applacation that demonstrates that when two identical names are compared and the case differs, the equals() method returns false, but the equalsIgnore() method returns true.

This is what I have . I just need someone to check it. I have no errors.

[code]
package week_4;

/**
*
* @author me
*/
import java.util.Scanner;
public class CompareCase
{
public static void main(String[] args)
{
String aName = "Dana";
String anotherName;
Scanner input = new Scanner(System.in);
System.out.print("Enter your name > ");
anotherName = input.nextLine();
if(aName.equals(anotherName)) {
System.out.println(aName + " equals " + anotherName);
}
else if(aName.equalsIgnoreCase(anotherName)) {
System.out.println(aName + " equals with ignore case " + anotherName); }
else {
System.out.println(aName + " is not equal to " + anotherName); }

}
}
[code]
Thanks

Explanation / Answer

please rate - thanks

your almost okay.

no matter what you should have a response for ignore case and for equals. I would also input both names

/**
*
* @author me
*/
import java.util.Scanner;
public class CompareCase
{
public static void main(String[] args)
{
String aName ;
String anotherName;
Scanner input = new Scanner(System.in);
System.out.print("Enter your name > ");
aName = input.nextLine();

System.out.print("Enter your name again > ");
anotherName = input.nextLine();
if(aName.equals(anotherName))
    System.out.println(aName + " equals " + anotherName+" with equals");
else
    System.out.println(aName + " doesn't equal " + anotherName+" with equals");


if(aName.equalsIgnoreCase(anotherName)) {
    System.out.println(aName + " equals with ignore case " + anotherName); }
else {
     System.out.println(aName + " is not equal to " + anotherName+" with ignore case"); }

}
}

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