The calculation puts out 0.0 for the Celsius. Can you help me? The textbook solu

Question

The calculation puts out 0.0 for the Celsius. Can you help me? The textbook solution did not give me any help.

import javax.swing.JOptionPane;
import javax.swing.JLabel;
import javax.swing.JFrame;

public class LabelFrame extends JFrame
{

private JLabel label; // converted temperature

public LabelFrame()
{
super( "Temperature Conversions" );

// obtain user input from JOptionPane input dialogs
String first =
JOptionPane.showInputDialog( "Enter Fahrenheit Temperature" );

// convert String input to int values for use in calculation
double num = Double.parseDouble( first );
double celsius = ( 5/9 * ( num - 32 ));


// displays temperature conversion
JLabel label = new JLabel( null, "The Celsius Temperture is " +celsius,
"Celsius Temperaturer", JLabel. );
add( label );

} // end method LabelFrame
} // end class LabelFrame



import javax.swing.JFrame;

public class LabelTest
{
public static void main( String args[] )
{
LabelFrame labelFrame = new LabelFrame(); // creates TemperatureConversion
labelFrame.setDefaultCloseOperation( JFrame.EXIT_ON_CLOSE);
labelFrame.setSize( 300, 300 ); // set frame size
labelFrame.setVisible( true ); // display frame

} // end method main
} // end class TemperatureConversionTest

Explanation / Answer

replace this

double celsius = ( 5/9 * ( num - 32 ));

with

double celsius = ( 5.0/9.0 * ( num - 32 ));

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