3.Write a program that inputs a date (date = 4, month = 12, and year = 2008) and

Question

3.Write a program that inputs a date (date = 4, month = 12, and year = 2008) and outputs the day of the week that corresponds to that date. The following algorithm is from http://en.wikipedia.org/wiki/Calculating_the_day_of_the_week. The implementation will require several functions:
bool isLeapYear(int year);
This function should return true if year is a leap year and false if it is not. Here is pseudocode to determine a leap year:
leap_year = ((year divisible by 400) or (year divisible by 4 and year not divisible by 100))
int getCenturyValue(int year);
This function should take the first two digits of the year (i.e. the century), divide by 4, and save the remainder. Subtract the remainder from 3 and return this value multiplied by 2. For example, the year 2008 becomes: (20/4) = 5 remainder 0. 3 – 0 = 3. Return 3 * 2 = 6.
int getYearValue(int year);
This function computes a value based on the years since the beginning of the century. First, extract the last two digits of the year. For example, 08 is extracted for 2008. Next, factor in leap years. Divide the value from the previous step by 4 and discard the remainder. Add the two results together and return this value. For example, from 2008 we extract 08. Then (8/4) = 2 remainder 0. Return 2 + 8 = 10.
int getMonthValue(int month, int year);
This function should return a value based on the table below and will require invoking the isLeapYear function:
Month
Return Value
January
0 (6 if year is a leap year)
February
3 (2 if year is a leap year)
March
3
April
6
May
1
June
4
July
6
August
2
September
5
October
0
November
3
December
5
Finally, to compute the day of the week, compute the sum of the date’s day plus the values returned by getMonthValue, getYearValue, and getCenturyValue. Divide the sum by 7 and compute the remainder. A remainder of 0 corresponds to Sunday, 1 corresponds to
Monday, etc. up to 6 which corresponds to Saturday. For example, the date July 4, 2008 should be computed as (day of month) + (getMonthValue) + (getYearValue) + (getCenturyValue) = 4 + 6 + 10 + 6 = 26. 26/7 = 3 remainder 5. The fifth day of the week corresponds to Friday.
Your program should allow the user to enter any date and output the corresponding day of the week in English.

Explanation / Answer

#include using namespace std; int main() { // PROTOTYPES int getCenturyValue(int year); int getYearValue(int year); int getMonthValue(int month, int year); // LOCAL DECLARATIONS char *DayOfWeek[] = { "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday" }; int day; int month; int year; int dayOfWeek; // PROCEDURES cout > day; cout > month; cout > year; cin.ignore(); dayOfWeek = getCenturyValue(year) + getYearValue(year) + getMonthValue(month, year) + day; dayOfWeek %= 7; cout

Related Questions

Navigate

• Browse (All)
• Browse 3
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.