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**PLEASE CHECK NUMBERS AND PROVIDE AN EXPLAINATION WITH FORMULAS** Problem 5-6 T

ID: 363052 • Letter: #

Question

**PLEASE CHECK NUMBERS AND PROVIDE AN EXPLAINATION WITH FORMULAS**

Problem 5-6

The following represents a project that should be scheduled using CPM:

b. What is the critical path?

c. What is the expected project completion time? (Round your answer to 3 decimal places.)

Project completion time= days

d. What is the probability of completing this project within 22 days? (Do not round intermediate calculations. Round your answer to 4 decimal places.)

Probability =

IMMEDIATE PREDECESSORS TIMES (DAYS) ACTIVITY a m b A — 1 4 7 B — 3 5 10 C A 2 5 8 D A 4 6 11 E B 1 2 3 F C,D 3 5 7 G D,E 1 2 6 H F,G 2 5 6

Explanation / Answer

Following table calculates Expected time as well as Standard deviation of each task :

Time ( Days)

Activity

a

M

B

Expected time , e = ( a + 4.m +b)/6

Standard deviation, Sd = ( b - a)/6

A

1

4

7

4

1.00

B

3

5

10

5.5

1.17

C

2

5

8

5

1.00

D

4

6

11

6.5

1.17

E

1

2

3

2

0.33

F

3

5

7

5

0.67

G

1

2

6

2.5

0.83

H

2

5

6

4.67

0.67

The predecessor diagram as follows :

                                                               A

             B

               C

                                         D

            E

                                         F

                                G

                                                                          H

The possible paths and their corresponding expected durations as follows :

A-C-F-H = 4 + 5 + 5 + 4.67 = 18.67 days

A-D-F-H = 4 + 6.5 + 5 + 4.67 = 20.17 days

A-D-G-H = 4 + 6.5 + 2.5 + 4.67 = 17.67 days

B-E-G-H = 5.5 + 2 + 2.5 + 4.67 = 14.67 days

Out of above , A-D-F-H has the longest duration and hence is the critical path and its duration 20.17 days is the project completion time

CRITICAL PATH = A-D-F-H

PROJECT COMPLETION TIME = 20.17 DAYS

Variance of the critical path

= Sum of variances of A ,D,F and H

= 1 + 1.17^2 +0.67^2 + 0.67^2

= 1 + 1.3689 + 0.4489 + 0.4489

= 3.2667

Therefore,

Standard deviation of the critical path = Sd = Square root ( 3.2667 ) = 1.807

Let the Z value corresponding to probability of completing the project in 22 days = Z1

Therefore,

Duration of critical path + Z1 x Standard deviation of critical path = 22

Or, 20.17 + 1.807.Z1 = 22

Or, 1.807.Z1 = 22 – 20.17 = 1.83

Or, Z1 = 1.83/1.807 = 1.012 ( 1.01 rounded to 2 decimal places )

Corresponding value of probability for Z1 = 1.01 from Normal distribution table = 0.84375

PROBABILITY OF COMPLETING THE PROJECT IN 22 DAYS = 0.8437

Time ( Days)

Activity

a

M

B

Expected time , e = ( a + 4.m +b)/6

Standard deviation, Sd = ( b - a)/6

A

1

4

7

4

1.00

B

3

5

10

5.5

1.17

C

2

5

8

5

1.00

D

4

6

11

6.5

1.17

E

1

2

3

2

0.33

F

3

5

7

5

0.67

G

1

2

6

2.5

0.83

H

2

5

6

4.67

0.67