Write a code to accept an input stream of no more than 60 characters and test wh

Question

Write a code to accept an input stream of no more than 60 characters and test whether the input stream forms a numerical palindrome. The code should ignore all characters that are not digits (so spaces, punctuation marks, letters, etc). Here is the beginning:

#include <stdio.h>
#include <stdlib.h>
#include <cytpe.h>

#define max_length 60

void main()
{
int c;
int input_chars[max_length];
int length;

printf ("Input the test phrase: ");

length = 0;

/* limit the length of the phrase to the first 60 chars */
/* do not store any non-digit input */

while ((c = getchar()) != ' ' && length < max_length) {
if (isdigit(c)) {
input_chars[length] = c - 48;
length++;
}
}


Complete the code in the following manner:
1. Print first all the numbers (digits) stored in the input_chars[] array.
2. Test the array for the presence of a numerical palindrome.
3. Double check to make sure it works!


Thank you in advance for your help! :)

Explanation / Answer

please rate - thanks

using your code

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#define max_length 60

int main()
{
int c;
int input_chars[max_length];
int length,i,j,good=1;

printf ("Input the test phrase: ");

length = 0;

/* limit the length of the phrase to the first 60 chars */
/* do not store any non-digit input */

while ((c = getchar()) != ' ' && length < max_length) {
if (isdigit(c)) {
             
     input_chars[length] = c - 48;
     length++;
}

}

j=length-1;
for(i=0;i<length/2;i++)
      {if(input_chars[i]!=input_chars[j])
           good=0;
      j--;
      }
printf("The numbers ");
for(i=0;i<length;i++)
    printf("%d",input_chars[i]);     
if(good==1)
    printf(" are a palindrone ");
else
    printf(" are not a palindrone ");

return 0;
}

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