You are the network administration for the small network in Figure 2. It consist
ID: 3637687 • Letter: Y
Question
You are the network administration for the small network in Figure 2. It consists of your headquarters location with a LAN with 60 hosts, remote office R1 with 10 hosts, and remote office R2 with 30 hosts. You have been assigned the address space 192.163.3.0/25. From this space you will need to create the subnets for each of the sites on your network and the two WAN links. Once you find the subnets assign addresses to the Routers interfaces and PCs using the following guidelines: Assign the first address from LAN subnets to the router interface connected to that LAN. Assign the second IP address in the LAN subnet to the PC on the LAN. Assign the first Address from WAN subnets to the HQ router end of the WAN link and the second address to the remote router interface. Use the steps below to help you work through it.
Create the subnets:
Address space: 192.163.3.0/25
Write it out in binary form identifying the host and network then use the space below in table as a scratch pad to help you in subnetting as needed. Remember to be efficient you usually want to start by creating the largest subnet you need first and then continue subnetting to find the smaller subnets in succession
Explanation / Answer
You have been given a /25 to work with, that's 128 addresses In decimal IP/mask format it's 192.163.3.0 mask 255.255.255.128 You need 60 addresses on the lan, so you halve it down to a /26 with 64 addresses For Remote R2, you'll halve the remaining space to a /27 with 32 addresses For R1, you'll halve what's left, to a /28 with 16 addresses, and then split the remainder into the two WAN links It's probably easier to keep track of the addressing if you take the larger subnets from the high side, so you'd begin with 192.163.3.64/26 (netmask 255.255.255.192), then 192.163.3.32/27 (netmask 255.255.255.224) The key binary place conversions Bit - decimal 00000001 - 1 00000010 - 2 00000100 - 4 00001000 - 8 00010000 - 16 00100000 - 32 01000000 - 64 10000000 - 128 In a netmask, when the mask bit is 1, the corresponding address bit is part of the net/subnet address, and while 0, is available as an address. The / format is another representation, with classic class A, B and C being /8, /16 and /24 - encompassing whole octets, while other values such as /25 use bits from the top of the next octet
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