Write a function mat_mult() that has accepts two 3x3 matrices matA and matB as i

Question

Write a function mat_mult() that has accepts two 3x3 matrices matA and matB as input and returns a pointer to an output matrix that is the product of the two input matrices. Pointers to MatA and MatB are passed from main() to mat_mult(). The output matrix is dynamically allocated on the heap. main() prints the contents of the output matrix. The prototype for mat_mult() is

int **mat_mult(int *matA, int *matB, int row, int col)



// Demonstrates how to allocate two dimensional dynamic arrays in C++
#include <iostream>

using namespace std;

int main()
{

int i, j;
int row = 3, col = 3;


// Allocate array in heap

// Allocate a row of pointers and store a pointer to this row of pointers in m
int **m = new int* [row];

// Allocate a column of integers and store a pointer to col i in m[i]
for (i = 0; i < row; i++)
m[i] = new int [col];

// Input array. Each array element is assigned the sum of its row and col values
for (i = 0; i < row; i++)
for (j = 0; j < col; j++)
m[i][j] = i + j;

// Output array
for (i = 0; i < row; i++) {
for (j = 0; j < col; j++)
cout << m[i][j] << " ";
cout << endl;
}
// Delete array
for (i = 0; i < row; i++)
delete [] m[i];
delete [] m;

return 0;
}





// Mat_Add is a function that returns a pointer to a matrix obtained by summing two input matrices

#include <iostream>

using namespace std;

int **Mat_Add(int *matA, int *matB, int row, int col);

int main()
{

int i, j;
int row = 3, col = 3;
int matA[row][col], matB[row][col];
int **matC;


// Input Arrray
for (i = 0; i < row; i++)
for(j = 0; j < col; j++) {
matA[i][j] = i + j;
matB[i][j] = i + j;
}

// Call the matrix addition function
matC = Mat_Add(&matA[0][0], &matB[0][0], row, col);

// Output array
for (i = 0; i < row; i++) {
for (j = 0; j < col; j++)
cout << matC[i][j] << " ";
cout << endl;
}


// Delete array
for (i = 0; i < row; i++)
delete [] matC[i];
delete [] matC;

return 0;

}

int **Mat_Add(int *matA, int *matB, int row, int col)
{
int i, j;

// Allocate array in heap

// Allocate a row of pointers and store a pointer to this row of pointers in m
int **temp = new int* [row];

// Allocate a column of integers and store a pointer to col i in m[i]
for (i = 0; i < row; i++)
temp[i] = new int [col];

// Input array. Each array element is assigned the sum of its row and col values
for (i = 0; i < row; i++)
for (j = 0; j < col; j++)
temp[i][j] = *(matA + i + j) + *(matB + i + j);

return temp;
}

Explanation / Answer

int main() { int i, j; int row = 3, col = 3; int matA[row][col], matB[row][col]; int **matC; // Input Arrray for (i = 0; i

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